我有一张Excel表格，其中我有近150列。我正在编写一个实用程序，在其中将获取列名称为X的列。在另一个线程中，我看到了如何读取XL工作簿和工作表..已编写以下代码..
HSSFSheet sheet = workbook.getSheetAt(0);
Iterator rows = sheet.rowIterator();
while (rows.hasNext())
{
HSSFRow row = (HSSFRow) rows.next();
Iterator cells = row.cellIterator();
List data = new ArrayList();
while (cells.hasNext())
{
HSSFCell cell = (HSSFCell) cells.next();
data.add(cell);
}
sheetData.add(data);
}
}
那么如何根据列名提取XL表中的确切列？
答案 0 :(得分：8)
Apache POI API HSSFSheet是基于行的，您需要通过itteration提取列数据，下面的链接可能会回答您的问题：
Extracting data in spreadsheet columns in Apache POI API
修改代码以搜索第一个工作表的第1行中的字符串
package projectTest.test;
import java.io.FileInputStream;
import java.util.ArrayList;
import java.util.List;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;
import org.apache.poi.poifs.filesystem.POIFSFileSystem;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
public class Poi {
public static void main(String[] args) throws Exception {
//test file is located in your project path
FileInputStream fileIn = new FileInputStream("test.xls");
//read file
POIFSFileSystem fs = new POIFSFileSystem(fileIn);
HSSFWorkbook filename = new HSSFWorkbook(fs);
//open sheet 0 which is first sheet of your worksheet
HSSFSheet sheet = filename.getSheetAt(0);
//we will search for column index containing string "Your Column Name" in the row 0 (which is first row of a worksheet
String columnWanted = "Your Column Name";
Integer columnNo = null;
//output all not null values to the list
List<Cell> cells = new ArrayList<Cell>();
Row firstRow = sheet.getRow(0);
for(Cell cell:firstRow){
if (cell.getStringCellValue().equals(columnWanted)){
columnNo = cell.getColumnIndex();
}
}
if (columnNo != null){
for (Row row : sheet) {
Cell c = row.getCell(columnNo);
if (c == null || c.getCellType() == Cell.CELL_TYPE_BLANK) {
// Nothing in the cell in this row, skip it
} else {
cells.add(c);
}
}
}else{
System.out.println("could not find column " + columnWanted + " in first row of " + fileIn.toString());
}
}
}
答案 1 :(得分：0)
这是非常简单有效的代码，按预期工作
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import org.apache.poi.openxml4j.exceptions.InvalidFormatException;
import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.ss.usermodel.Sheet;
import org.apache.poi.ss.usermodel.Workbook;
import org.apache.poi.ss.usermodel.WorkbookFactory;
public class TestExcelFile {
public static void main(String[] args) {
String envFilePath = System.getenv("AZURE_FILE_PATH");
// upload list of files/directory to blob storage
File folder = new File(envFilePath);
File[] listOfFiles = folder.listFiles();
for (int i = 0; i < listOfFiles.length; i++) {
if (listOfFiles[i].isFile()) {
System.out.println("File " + listOfFiles[i].getName());
Workbook workbook;
//int masterSheetColumnIndex = 0;
try {
workbook = WorkbookFactory.create(new FileInputStream(envFilePath + "\\"+ listOfFiles[i].getName()));
// Get the first sheet.
Sheet sheet = workbook.getSheetAt(0);
// Get the first cell.
Row row = sheet.getRow(0);
//Cell cell = row.getCell(0);
for (Cell cell1 : row) {
// Show what is being read.
System.out.println(cell1.toString());
//masterSheetColumnIndex++;
}
//we will search for column index containing string "Your Column Name" in the row 0 (which is first row of a worksheet
String columnWanted = "Modality Name";
Integer columnNo = null;
//output all not null values to the list
List<Cell> cells = new ArrayList<Cell>();
Row firstRow = sheet.getRow(0);
for(Cell cell1:firstRow){
if (cell1.getStringCellValue().equals(columnWanted)){
columnNo = cell1.getColumnIndex();
}
}
if (columnNo != null){
for (Row row1 : sheet) {
Cell c = row1.getCell(columnNo);
if (c == null || c.getCellType() == Cell.CELL_TYPE_BLANK) {
// Nothing in the cell in this row, skip it
} else {
cells.add(c);
}
}
System.out.println("");
}else{
System.out.println("could not find column " + columnWanted + " in first row of " + listOfFiles[i].getName());
}
} catch (InvalidFormatException | IOException e) {
e.printStackTrace();
}
}
}
}
}
答案 2 :(得分：0)
File myFile = new File(path);
FileInputStream fis = new FileInputStream(myFile);
// Finds the workbook instance for XLSX file
XSSFWorkbook myWorkBook = new XSSFWorkbook (fis);
//XSSFWorkbook workBook = new XSSFWorkbook();
//Reading sheet at number 0 in spreadsheet(image attached for reference
Sheet sheet = myWorkBook.getSheetAt(0);
//creating a Sheet object to retrieve object
Iterator<Row> itr = sheet.iterator();//iterating over excel file
while (itr.hasNext())
{
Row row = itr.next();
Iterator<Cell> cellIterator = row.cellIterator();//iterating over each column
//Reading cell in my case column name is ppm
Cell ppmEx= row.getCell(0);
//Cell cell = cellIterator.next();
while (cellIterator.hasNext())
{
Cell cell = cellIterator.next();
//Check the cell type and format accordingly
switch (cell.getCellType())
{
case Cell.CELL_TYPE_NUMERIC:
//System.out.println(cell.getNumericCellValue() + " ");
al.add(cell.getNumericCellValue());
break;
case Cell.CELL_TYPE_STRING:
//System.out.println(cell.getStringCellValue()+" ");
al.add(cell.getStringCellValue());
break;
case Cell.CELL_TYPE_BOOLEAN:
//System.out.println(cell.getBooleanCellValue()+" ");
al.add(cell.getBooleanCellValue());
case Cell.CELL_TYPE_BLANK:
//System.out.println("blank");
al.add("blank");
}
}
System.out.println("-");
}
答案 3 :(得分：0)
您也可以这样尝试。您可以遍历标题行。
Row headerRow = sheet.get(0);
for (int cellIndex = 0; cellIndex < 150; cellIndex++) {
Cell cell = row.getCell(cellIndex);
if (columnName.equals(cell.getStringCellValue())) {
// do your thing
}
}
注意：如果您的单元格可能为空，请使用：
Cell cell = row.getCell(cellIndex);
if (cell!=null) {
if (columnName.equals(cell.getStringCellValue())) {
// do your thing
}
}
我希望这会有所帮助！