我需要对此进行反序列化。
{"previous_cursor_str":"0","next_cursor":0,"ids":[741999686,240455509,126524150,143548100,124328422,624776268,393738125,587829914,280834485,64818350,282713007,90425850,759794,164401208,114771958,114364910,89725893],"previous_cursor":0,"next_cursor_str":"0"}
任何想法?
答案 0 :(得分:4)
它的JObject真的有一个Id的数组。
首先,你可以像这样创建一个代表json的类:
public class RootObject
{
public string previous_cursor_str { get; set; }
public int next_cursor { get; set; }
public List<int> ids { get; set; }
public int previous_cursor { get; set; }
public string next_cursor_str { get; set; }
}
然后将json反序列化为对象,执行此操作:
var myJsonObject = JsonConvert.DeserializeObject<RootObject>(jsonString);
或者如果您只想在数组中使用ID:
var obj = JObject.Parse(jsonstring);
var idArray = obj["ids"].Children().Select(s=>s.value<string>());
答案 1 :(得分:0)
刚试过https://jsonclassgenerator.codeplex.com/并获得了以下代码。哪个是白色和geepie的类一样。好工具。
using System;
using System.Collections.Generic;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
namespace Example
{
class Result
{
[JsonProperty("previous_cursor_str")]
public string PreviousCursorStr { get; set; }
[JsonProperty("next_cursor")]
public int NextCursor { get; set; }
[JsonProperty("ids")]
public IList<int> Ids { get; set; }
[JsonProperty("previous_cursor")]
public int PreviousCursor { get; set; }
[JsonProperty("next_cursor_str")]
public string NextCursorStr { get; set; }
}
public static unsafe void Main()
{
Result result = JsonConvert.DeserializeObject<Result> (" ... your string ...");
Console.WriteLine(result);
}
}