我正在尝试选择仅包含电话号码的联系人。我正在关注this code
static final int PICK_CONTACT_REQUEST = 1; // The request code
...
private void pickContact() {
Intent pickContactIntent = new Intent(Intent.ACTION_PICK, new Uri("content://contacts"));
pickContactIntent.setType(Phone.CONTENT_TYPE); // Show user only contacts w/ phone numbers
startActivityForResult(pickContactIntent, PICK_CONTACT_REQUEST);
}
但不幸的是,它显示错误:Cannot instantiate the type Uri
实际上我有另一个正常运行的工作代码,但在选择电子邮件联系人时崩溃了。我只需要电话号码。
Intent intentContact = new Intent(Intent.ACTION_PICK,
ContactsContract.Contacts.CONTENT_URI);
intentContact.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivityForResult(intentContact, PICK_CONTACT);
并且在onReceive()
,此方法称为
public void getContactInfo(Intent intent) {
ContentResolver cr = getContentResolver();
cursor = cr.query(intent.getData(), null, null, null, null);
while (cursor.moveToNext()) {
String contactId = cursor.getString(cursor
.getColumnIndex(ContactsContract.Contacts._ID));
if (Integer
.parseInt(cursor.getString(cursor
.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor phones = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID
+ " = " + contactId, null, null);
while (phones.moveToNext()) {
phoneNumber = phones
.getString(phones
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
}
phones.close();
} else {
snipp.showAlertDialog(getApplicationContext(), "No Number",
"Cannot read number", false);
}
}
cursor.close();
}
答案 0 :(得分:10)
这对我有用:
private void pickContact() {
Intent pickContactIntent = new Intent( Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI );
pickContactIntent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_TYPE);
startActivityForResult(pickContactIntent, PICK_CONTACT_REQUEST);
}
修改强>
您的onActivityResult()
应如下所示:
@Override
public void onActivityResult( int requestCode, int resultCode, Intent intent ) {
super.onActivityResult( requestCode, resultCode, intent );
if ( requestCode == PICK_CONTACT_REQUEST ) {
if ( resultCode == RESULT_OK ) {
Uri pickedPhoneNumber = intent.getData();
// handle the picked phone number in here.
}
}
}
}
答案 1 :(得分:5)
使用Uri.parse()代替。你不能直接破坏Uri