我使用Spring Security根据Active Directory服务器对用户进行身份验证。 CustomUserContext也会注入ldapAuthenticationProvider bean,以提供对其他LDAP属性的访问。一切都很好。我没有问题从认证用户那里拉出我想要的东西。
我遇到的问题是我想要从登录用户以外的用户的Active Directory服务器中检索一些属性,特别是电子邮件地址。是否可以通过利用我已经拥有的内容来实现这一点有或者我唯一的选择是使用完全独立的方法来访问来自不同用户的LDAP属性吗?
[编辑] 配置如下
安全-config.xml中
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:sec="http://www.springframework.org/schema/security"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">
<bean id="contextSource" class="org.springframework.ldap.core.support.LdapContextSource">
<property name="url" value="ldap://xxxx.xxxx.xxx:389" />
<property name="base" value="dc=corp,dc=global,dc=xxxxx,dc=com" />
<property name="userDn" value="CN=lna.authquery,OU=LDAPGroups,OU=NorthAmerica,DC=corp,DC=global,DC=xxxxx,DC=com" />
<property name="password" value="xxxxxxx" />
<property name="pooled" value="true" />
<!-- AD Specific Setting for avoiding the partial exception error -->
<property name="referral" value="follow" />
</bean>
<bean id="ldapAuthenticationProvider" class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider" >
<constructor-arg>
<bean class="org.springframework.security.ldap.authentication.BindAuthenticator">
<constructor-arg ref="contextSource" />
<property name="userSearch">
<bean id="userSearch" class="org.springframework.security.ldap.search.FilterBasedLdapUserSearch">
<constructor-arg index="0" value="" />
<constructor-arg index="1" value="(sAMAccountName={0})" />
<constructor-arg index="2" ref="contextSource" />
</bean>
</property>
</bean>
</constructor-arg>
<constructor-arg>
<bean class="org.springframework.security.ldap.userdetails.DefaultLdapAuthoritiesPopulator">
<constructor-arg ref="contextSource" />
<constructor-arg value="" />
<property name="groupSearchFilter" value="(member={0})" />
<property name="searchSubtree" value="true" />
<!-- Settings below convert the adds the prefix ROLE_ to roles returned from AD -->
</bean>
</constructor-arg>
<property name="userDetailsContextMapper">
<bean class="net.xxxx.xxxxx.utilities.CustomUserDetailsContextMapper" />
</property>
</bean>
<bean id="authenticationManager" class="org.springframework.security.authentication.ProviderManager">
<constructor-arg>
<list>
<ref local="ldapAuthenticationProvider" />
</list>
</constructor-arg>
</bean>
<sec:http pattern="/css/**" security="none"/>
<sec:http pattern="/images/**" security="none"/>
<sec:http auto-config="true" authentication-manager-ref="authenticationManager" >
<sec:intercept-url pattern="/login.jsp*" requires-channel="https" access="IS_AUTHENTICATED_ANONYMOUSLY"/>
<sec:intercept-url pattern="/**" requires-channel="https" access="IS_AUTHENTICATED_FULLY"/>
<sec:form-login login-page='/login.jsp'
default-target-url="/home.html"
authentication-failure-url="/login.jsp" />
</sec:http>
CustomeUserDetails.java
package net.xxxx.xxxx.utilities;
import java.util.Collection;
import org.springframework.security.core.GrantedAuthority;
import org.springframework.security.core.userdetails.User;
public class CustomUserDetails extends User {
private static final long serialVersionUID = 1416132138315457558L;
// extra instance variables
final String fullname;
final String email;
final String title;
public CustomUserDetails(String username, String password, boolean enabled, boolean accountNonExpired,
boolean credentialsNonExpired, boolean accountNonLocked,
Collection<? extends GrantedAuthority> authorities, String fullname,
String email, String title) {
super(username, password, enabled, accountNonExpired, credentialsNonExpired,
accountNonLocked, authorities);
this.fullname = fullname;
this.email = email;
this.title = title;
}
public String getFullname() {
return this.fullname;
}
public String getEmail() {
return this.email;
}
public String getTitle() {
return this.title;
}
}
CustomUserDetailsContextMapper.java
package net.xxxx.xxxxx.utilities;
import java.util.Collection;
public class CustomUserDetailsContextMapper implements UserDetailsContextMapper {
public UserDetails mapUserFromContext(DirContextOperations ctx,
String username, Collection<? extends GrantedAuthority> authorities) {
String fullname = "";
String email = "";
String title = "";
Attributes attributes = ctx.getAttributes();
try {
fullname = (String) attributes.get("displayName").get();
email = (String) attributes.get("mail").get();
title = (String) attributes.get("title").get();
} catch (NamingException e) {
e.printStackTrace();
}
CustomUserDetails details = new CustomUserDetails(username, "", true, true, true, true, authorities, fullname, email, title);
return details;
}
public void mapUserToContext(UserDetails user, DirContextAdapter ctx) {
}
}
答案 0 :(得分:7)
我终于弄清楚了如何做到这一点。我正在回答这个问题,以防其他人需要这样做。如果我是唯一一个,我会感到惊讶。
首先,我必须将我的security-config.xml
文件移出WEB-INF结构并将其放在spring资源目录下。我能够重用的contextSource
bean。但是,我无法重用CustomUserDetailsContextMapper.java
和CustomUserDetails.java
类,因为它们太过于特定于Spring安全性而不是仅仅从未经身份验证的用户检索LDAP数据。
我最后为LDAP访问编写了一个单独的类,其中有一个公共contextSource
自动装入。该类在下面。
<强> LdapDao.java 强>
package net.xxxxx.xxx.dao;
import java.util.HashMap;
import java.util.LinkedList;
import java.util.Map;
import javax.naming.directory.Attributes;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.ldap.core.AttributesMapper;
import org.springframework.ldap.core.LdapTemplate;
import org.springframework.ldap.core.support.LdapContextSource;
import org.springframework.stereotype.Component;
@Component
public class LdapDao {
LdapTemplate template;
@Autowired
public LdapDao(LdapContextSource contextSource) {
template = new LdapTemplate(contextSource);
}
@SuppressWarnings("unchecked")
public Map<String, String> getUserAttributes(String username) {
Map<String, String> results = new HashMap<String, String>();
String objectClass = "samAccountName=" + username;
LinkedList<Map<String, String>> list = (LinkedList<Map<String, String>>) template.search("", objectClass, new UserAttributesMapper());
if (!list.isEmpty()) {
// Should only return one item
results = list.get(0);
}
return results;
}
private class UserAttributesMapper implements AttributesMapper {
@Override
public Map<String, String> mapFromAttributes(Attributes attributes) throws javax.naming.NamingException {
Map<String, String> map = new HashMap<String, String>();
String fullname = (String) attributes.get("displayName").get();
String email = (String) attributes.get("mail").get();
String title = (String) attributes.get("title").get();
map.put("fullname", fullname);
map.put("email", email);
map.put("title", title);
return map;
}
}
}
答案 1 :(得分:4)
@Bill你所做的很棒,虽然实际上有一种更简单的方法。不要诉诸LdapTemplate
,只需使用您已为DefaultLdapAuthoritiesPopulator
和FilterBasedLdapUserSearch
注册的bean。这样,您就可以获得相同的UserDetails
对象,该对象也会填充权限并重新使用您net.xxxx.xxxxx.utilities.CustomUserDetailsContextMapper
的现有代码。
以下是您需要做的事情:
ref
属性和constructor-arg
s DefaultLdapAuthoritiesPopulator
,FilterBasedLdapUserSearch
,net.xxxx.xxxxx.utilities.CustomUserDetailsContextMapper
)。LdapDao
注入引用中:
FilterBasedLdapUserSearch
- userSearch
DefaultLdapAuthoritiesPopulator
- authPop
net.xxxx.xxxxx.utilities.CustomUserDetailsContextMapper
- userMapper
LdapDao
:
public UserDetails getUserDetails(final String username) {
try {
DirContextOperations ctx = userSearch.searchForUser(username);
return userMapper.mapUserFromContext(ctx, username,
authPop.getGrantedAuthorities(ctx, username));
} catch (UsernameNotFoundException ex) {
return null;
}
}
现在你可以调用getUserDetails(String)
来获取你在检索当前登录的上下文时所做的相同对象,并且可以使用相同的代码等。