Question

意识到我不得不担心基于网络的线程在我的UI线程上造成破坏，我经历了为我的TCP / IP网络创建自定义处理程序和自定义线程的整个过程。远程服务器。工作得很好。（您将在下面的代码中看到它被引用为mainCommunicationThread(controlCommands);）

在触发该线程/处理程序之前，我从SQL中提取IP或主机名，（称之为currIPstr）然后将其与一堆其他变量一起发送到线程/处理程序。我需要做的一件事是确保它是A）一个有效的IP地址，或者B）主机名被解析 - 否则，即使开始尝试也没有意义。

好的，没问题，我只是这样称呼：

currIP = InetAddress.getByName(currIPstr).toString().split("/")[1];

我刚刚遇到的是，当Gingerbread或StrictMode运行时，上面的行触发了可怕的NetworkOnMainThreadException。

是的，对InetAddress.getByName的简单调用就足够了。好吧，我一直在努力解决这个问题，所以我将整个功能移到了一个可运行的地方：

private String currStatIP = null;
private String currentStatIPstr = null;
private Integer currentStatIDstr = -1;
private String currentPort = null;
private String currentLocation = null;
private String currUserName = null;
private String currPassword = null;
private Integer currStatID = -1;
public void StatControl(Cursor c, final String[] commandtosend){


    /*the object will always start off with the first 4 fields being the current login information.
     * [0] = IP Address
     * [1] = port number
     * [2] = username
     * [3] = password
     * [4] = COMMAND -- this will be used in a switchcase inside the pingpong to decide what to do.
     *               -- if the Socket is not open, the first 4 fields will be used to re-initiate the connection
     *               -- otherwise, the command is drawn from this field and sent directly.
     * */


    currentStatIDstr = c.getInt(0);
    currentStatIPstr = c.getString(1);
    currentPort = c.getString(2);
    currentLocation = c.getString(3);
    currUserName = c.getString(4);
    currPassword = c.getString(5);
    currStatID = currentStatIDstr;


    Handler networkLookupHandler = new Handler();
    Runnable networkLookupRunnable = new Runnable() {
         public void run() {
             try {
                    currStatIP = InetAddress.getByName(currentStatIPstr).toString().split("/")[1];
                } catch (UnknownHostException e) {
                    e.printStackTrace();
                }
             int portNumber = 0;
                try {
                    portNumber = Integer.parseInt(currentPort);
                } catch(NumberFormatException nfe) {
                   nfe.printStackTrace();
                }
                String userName = currUserName;
                String passWord = currPassword;
                String[] command = commandtosend;

                Object[] controlCommands = new Object[]{
                        currStatID,
                        currStatIP, //InetAddress of String representing the IP address
                        portNumber,     //int representation of the port number, taken from String
                        currentLocation,
                        userName,
                        passWord,
                        command
                        };
                /*for(int i=0;i<controlCommands.length;i++){
                    Log.d("object work","controlCommands[" + i + "] is " + controlCommands[i]);
                }*/

                mainCommunicationThread(controlCommands);
         }   
    };
    networkLookupHandler.post(networkLookupRunnable);
}

而且，是的！有效！我不再收到NetworkOnMainThreadException了。哦......等等..是的。

以上不会在API 10,12,14上触发异常，即使16在模拟器中工作正常，但是，如果我将其加载到运行Jellybean 4.1.1的Samsung Google Galaxy Nexus上，我会收到NetworkOnMainThreadException崩溃。即使上面包裹着runnable。

我完全不知道如何解决这个问题。

Answer 1

您正试图在runnable中运行网络操作，因此尝试在onCreate方法中添加此代码：

     StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
     StrictMode.setThreadPolicy(policy);

或者我建议您使用asynctask而不是使用Runnable线程

Answer 2

我的解决方案：

public static InetAddress getInetAddressByName(String name)
{
    AsyncTask<String, Void, InetAddress> task = new AsyncTask<String, Void, InetAddress>()
            {

                @Override
                protected InetAddress doInBackground(String... params)
                {
                    try
                    {
                        return InetAddress.getByName(params[0]);
                    }
                    catch (UnknownHostException e)
                    {           
                        return null;
                    }                       
                }           
            };
    try
    {
        return task.execute(name).get();
    }
    catch (InterruptedException e)
    {
        return null;
    }
    catch (ExecutionException e)
    {
        return null;
    }

}

Answer 3

我通过在新线程中运行它解决了我的Inet6Address.getLocalHost（）NetworkOnMainThreadException问题。

InetAddress.getByName导致NetworkOnMainThreadException

3 个答案: