Question

目前正在处理该报告。我需要的是样本表，

Instance Type   Sep-23  Sep-16  Sep-09  Sep-02  Aug-26  Aug-19
-------------------------------------------------------------------------
Early ASN        4        2      4        1       1       2
Late ASN         2        1      5        3       1       1
     Sum         6        3      9        4       2       3

但实际表是，

SPGI01_INSTANCE_TYPE_C  SPGI01_CREATE_S
--------------------------------------------------------------
Early ASN                9/17/2012 12:00:00.000
Early ASN           9/18/2012 10:06:11.000
Early ASN           9/19/2012 8:00:04.000
Early ASN           9/20/2012 3:00:05.000
Early ASN           9/10/2012 12:00:07.000
Early ASN           9/11/2012 12:00:32.000
Early ASN           9/3/2012 12:00:17.000
Early ASN           9/4/2012 10:06:00.000
Early ASN           9/5/2012 8:00:00.000
Early ASN           9/6/2012 3:00:00.000
Early ASN           8/31/2012 12:00:00.000
Early ASN           8/26/2012 12:00:00.000
Early ASN           8/14/2012 12:00:00.000
Early ASN           8/15/2012 12:00:00.000
Late ASN            9/17/2012 12:00:00.000
Late ASN            9/18/2012 10:06:00.000
Late ASN            9/11/2012 12:00:00.000
Late ASN            9/3/2012 12:00:00.000
Late ASN            9/4/2012 10:06:00.000
Late ASN            9/5/2012 8:00:00.000
Late ASN            9/6/2012 3:00:00.000
Late ASN            9/6/2012 2:00:00.000
Late ASN            8/31/2012 12:00:00.000
Late ASN            8/31/2012 12:00:00.000
Late ASN            8/31/2012 12:00:00.000
Early ASN           8/15/2012 12:00:00.000

我需要按照“SPGI01_INSTANCE_TYPE_C”列进行分组，并将每周星期日分组到最后六周的星期日。在这里我粘贴了两个样本表，一张表是我想要的，另一张表就是我所拥有的。给我解决方案。

我的查询是，

SELECT distinct I01.[SPGI01_INSTANCE_TYPE_C],
count (I01.[SPGI01_INSTANCE_TYPE_C])
  FROM [SUPER-G].[dbo].[CSPGI01_ASN_ACCURACY] I01,
  [SUPER-G].[dbo].[CSPGI50_VALID_INSTANCE_TYPE] I50

where
I01.[SPGA02_BUSINESS_TYPE_C] = 'prod'
and
I01.[SPGA03_REGION_C] in( 'ap','na','sa','eu')
and 
I01.[SPGI01_SUB_BUSINESS_TYPE_C] = 'PRD'
and
(I01.[SPGI01_CREATE_S] between '2012-01-01 12:00:00.000' AND DATEADD(day , 7, '2012-01-15 00:00:00.000'))

and
I01.[SPGI01_EXCEPTIONED_F] = 'N'
and
I01.[SPGI01_DISPUTED_F] != 'Y'
and
I50.[SPGI50_INSTANCE_TYPE_C] = I01.[SPGI01_INSTANCE_TYPE_C]
and 
I50.[SPGA04_RATING_ELEMENT_D] = 1
group by I01.[SPGI01_INSTANCE_TYPE_C]

Answer 1

我对您发布的数据做了一些假设。

首先，您发布的值均为2011，但最终结束日期为列标题与2011不对应，它们是Sunday的{{1}}值所以我改变了数据。同样，2012的最终条目，我相信应该是Early ASN 8/15/2011 12:00条目，否则要完成的总数匹配。

要获得结果，您希望自己想要应用PIVOT功能。此功能允许您聚合值，然后将它们转换为列。

Late ASN

请参阅SQL Fiddle with Demo

如何按每周分组到最后六周的星期日日期在sql？

1 个答案: