View v = rootView.findViewById(R.id.layout1);
if (v != null) {
v.buildDrawingCache();
Bitmap bitmap = v.getDrawingCache();
canvas.drawBitmap(bitmap, dummyMatrix, null);
v.destroyDrawingCache();
}
我有这个代码。但是我需要截取我的所有ListView项目,但是如果我的列表视图中有多个项目而不是屏幕上可见的项目,则当代码大于可见矩形时,此代码不会捕获。
如何正确捕获我的ListView?
我创建的新工作代码
public static Bitmap getWholeListViewItemsToBitmap() {
ListView listview = MyActivity.mFocusedListView;
ListAdapter adapter = listview.getAdapter();
int itemscount = adapter.getCount();
int allitemsheight = 0;
List<Bitmap> bmps = new ArrayList<Bitmap>();
for (int i = 0; i < itemscount; i++) {
View childView = adapter.getView(i, null, listview);
childView.measure(MeasureSpec.makeMeasureSpec(listview.getWidth(), MeasureSpec.EXACTLY),
MeasureSpec.makeMeasureSpec(0, MeasureSpec.UNSPECIFIED));
childView.layout(0, 0, childView.getMeasuredWidth(), childView.getMeasuredHeight());
childView.setDrawingCacheEnabled(true);
childView.buildDrawingCache();
bmps.add(childView.getDrawingCache());
allitemsheight+=childView.getMeasuredHeight();
}
Bitmap bigbitmap = Bitmap.createBitmap(listview.getMeasuredWidth(), allitemsheight, Bitmap.Config.ARGB_8888);
Canvas bigcanvas = new Canvas(bigbitmap);
Paint paint = new Paint();
int iHeight = 0;
for (int i = 0; i < bmps.size(); i++) {
Bitmap bmp = bmps.get(i);
bigcanvas.drawBitmap(bmp, 0, iHeight, paint);
iHeight+=bmp.getHeight();
bmp.recycle();
bmp=null;
}
return bigbitmap;
}
答案 0 :(得分:43)
工作代码:
public static Bitmap getWholeListViewItemsToBitmap() {
ListView listview = MyActivity.mFocusedListView;
ListAdapter adapter = listview.getAdapter();
int itemscount = adapter.getCount();
int allitemsheight = 0;
List<Bitmap> bmps = new ArrayList<Bitmap>();
for (int i = 0; i < itemscount; i++) {
View childView = adapter.getView(i, null, listview);
childView.measure(MeasureSpec.makeMeasureSpec(listview.getWidth(), MeasureSpec.EXACTLY),
MeasureSpec.makeMeasureSpec(0, MeasureSpec.UNSPECIFIED));
childView.layout(0, 0, childView.getMeasuredWidth(), childView.getMeasuredHeight());
childView.setDrawingCacheEnabled(true);
childView.buildDrawingCache();
bmps.add(childView.getDrawingCache());
allitemsheight+=childView.getMeasuredHeight();
}
Bitmap bigbitmap = Bitmap.createBitmap(listview.getMeasuredWidth(), allitemsheight, Bitmap.Config.ARGB_8888);
Canvas bigcanvas = new Canvas(bigbitmap);
Paint paint = new Paint();
int iHeight = 0;
for (int i = 0; i < bmps.size(); i++) {
Bitmap bmp = bmps.get(i);
bigcanvas.drawBitmap(bmp, 0, iHeight, paint);
iHeight+=bmp.getHeight();
bmp.recycle();
bmp=null;
}
return bigbitmap;
}
答案 1 :(得分:6)
虽然无法制作尚未呈现内容的屏幕截图(如ListView的屏幕外项目),但您可以制作多个屏幕截图,在每个镜头之间滚动内容,然后加入图像。这是一个可以为您自动执行此操作的工具:https://github.com/PGSSoft/scrollscreenshot
免责声明:我是此工具的作者,由my employer发布。欢迎提出功能请求。
答案 2 :(得分:0)
使用此功能获取列表视图的位图
public Bitmap getBitmapFromView(View view) {
Bitmap returnedBitmap = Bitmap.createBitmap(view.getMeasuredWidth(),
view.getMeasuredHeight() , Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(returnedBitmap);
Drawable bgDrawable = view.getBackground();
if (bgDrawable != null)
bgDrawable.draw(canvas);
else
canvas.drawColor(Color.WHITE);
view.draw(canvas);
return returnedBitmap;
}
将其用作
Bitmap b = getBitmapFromView(your listview object here);
并根据需要使用此位图
希望有所帮助..
答案 3 :(得分:0)
如果生成的位图具有黑色背景。这是因为您查看无法从xml文件中获取颜色。所以设置你的视图颜色
Ether / IP / ICMP 192.168.1.74 > 192.168.1.84 echo-request 0 / Raw
Ether / IP / ICMP 192.168.1.84 > 192.168.1.74 echo-reply 0 / Raw
Ether / IPv6 / ICMPv6 Echo Request (id: 0x306 seq: 0x3bb)
Ether / IPv6 / ICMPv6 Echo Request (id: 0x306 seq: 0x3bb)
Ether / IPv6 / ICMPv6 Echo Reply (id: 0x306 seq: 0x3bb)
Ether / IPv6 / ICMPv6 Echo Reply (id: 0x306 seq: 0x3bb)
Ether / IP / TCP 192.168.1.84:ssh > 192.168.1.74:61336 PA / Raw
Ether / IP / TCP 192.168.1.74:61336 > 192.168.1.84:ssh A
Ether / IP / ICMP 192.168.1.74 > 192.168.1.84 echo-request 0 / Raw
Ether / IP / ICMP 192.168.1.84 > 192.168.1.74 echo-reply 0 / Raw