我刚刚从C开始,对幕后发生的事情一无所知。我正在为数据结构类动态学习它,这使得事情变得更加艰难。
更新:我已经取消了程序,并开始使用内存并启动。我在那里有allocate和deallocate函数,我得到一个malloc错误:Q1(9882)malloc: *对象0x7fff59daec08的错误:被释放的指针未被分配 * 在malloc_error_break中设置断点以进行调试
Update2这是我的修改后的代码,它仍然缺少一些东西,我的几个printf语句没有出现:
#include <stdio.h>
#include<stdlib.h>
#include<math.h>
#include<assert.h>
static int size = 10;
struct student{
int id;
int score;
};
struct student* allocate(){
/*Allocate memory for ten students*/
struct student *s = malloc(size*(sizeof(struct student)));
assert(s != 0);
/*return the pointer*/
return s;
}
void generate(struct student* students){
/*Generate random ID and scores for ten students, ID being between 1 and 10, scores between 0 and 100*/
srand((unsigned int)time(NULL));
int id[size];
int y;
for (int i = 0; i < size; i++){
y = rand() % size + 1;
while(dupe(id, i, y)){
y = rand() % size + 1;
}
id[i] = y;
}
for (int j = 0; j < size; j++){
(students + j)->id = id[j];
(students + j)->score = rand() % 101;
printf("ID: %d\tScore: %d\n", (students + j)->id, (students + j)->score);
}
}
int dupe(int id[], int size1, int i){
for (int x = 0; x < size1; x++){
if(id[x] == i)
return 1;
}
return 0;
}
void output(struct student* students){
/*Output information about the ten students in the format:
ID1 Score1
ID2 score2
ID3 score3
...
ID10 score10*/
sort(&students);
for(int x = 0; x < size; x++){
printf("ID: %d\tScore: %d\n", (students + x)->id, (students + x)->score); //print stmt not showing
}
}
void sort(struct student* students){
struct student *sd = allocate();
struct student *stud;
for(int i = 0; i < size; i++){
stud = &students[i];
sd[stud->id] = *stud;
}
for(int x = 0; x < size; x++){
printf("ID: %d\tScore: %d\n", (sd + x)->id, (sd + x)->score); //print stmt not showing
}
students = &sd;
deallocate(sd);
}
void summary(struct student* students){
/*Compute and print the minimum, maximum and average scores of the ten students*/
}
void deallocate(struct student* stud){
/*Deallocate memory from stud*/
free(stud);
}
int main(){
struct student* stud = NULL;
char c[] = "------------------------------\n";
/*call allocate*/
stud = allocate();
/*call generate*/
generate(&stud);
/*call output*/
printf("%s", c);
output(&stud);
/*call summary*/
/*call deallocate*/
deallocate(stud);
return 0;
}
答案 0 :(得分:4)
students = &students[x];
这会改变students
点的位置,所以下一次循环你将从那里开始,而不是从头开始。也就是说,您正在获得originalstudents[0]
,originalstudents[1]
,originalstudents[1+2]
,originalstudents[1+2+3]
等。sd
存在同样的问题。
相反,您想要使用其他变量,例如
struct student* st = &students[x];
printf("id = %d\tscore = %d\n", st->id, st->score);
etc
另外,什么是sd?你似乎没有明显的理由分配一些空间并将学生复制到sd。分配的空间不会被保存或返回......这是内存泄漏。哦,等等,我明白了......你按照他们的身份对sd的学生进行了重新排序。所以你应该在完成后释放内存。但是对于学生和sd,你需要一个指向数组的不同指针而不是数组元素。您可以使用许多不同的命名约定,但最好使用一致的命名约定。例如:
void output(struct Student* students){
struct Student *idstudents = allocate(); /* sorted by id */
if (!idstudents)
/* handle allocation error */;
for (int x = 0; x < 10; x++){
struct Student* student = &students[x];
printf("id = %d\tscore = %d\n", student->id, student->score);
struct Student* idstudent = &idstudents[student->id];
*idstudent = *student; /* copy all fields at once */
printf("id = %d\tscore = %d\n", idstudent->id, idstudent->score);/* pointless here, since we just printed the same info via student */
}
for (int x = 0; x < 10; x++){
struct Student* idstudent = &idstudents[x];
printf("id = %d\tscore = %d\n", idstudent->id, idstudent->score);
}
deallocate(idstudents);
}
答案 1 :(得分:1)
您的output()
函数误用了指针,因此您正在践踏您的学生数据。尝试这样的事情(假设ID是数组索引,因为这就是你使用它们的方式):
struct student* allocate()
{
/*Allocate memory for ten students*/
struct student *s = malloc(10 * sizeof(struct student));
assert(s != NULL);
/*return the pointer*/
return s;
}
void deallocate(struct student* stud)
{
/*Deallocate memory from stud*/
free(stud);
}
int main()
{
struct student* stud = NULL;
/*call allocate*/
stud = allocate();
/*call generate*/
/*call output*/
output(stud);
/*call summary*/
/*call deallocate*/
deallocate(stud);
return 0;
}
void output(struct student* students)
{
/*allocate array for sorting*/
struct student *sd = allocate();
struct student *stud;
/*make copy of students in sorted order*/
for (int x = 0; x < 10; ++x)
{
stud = &students[x];
printf("id = %d\tscore = %d\n", stud->id, stud->score);
sd[stud->id] = *stud;
}
/*output sorted students*/
for (int x = 0; x < 10; ++x)
{
stud = &sd[x];
printf("id = %d\tscore = %d\n", stud->id, stud->score);
}
/*deallocate array for sorting*/
deallocate(sd);
}
由于您已经对学生数量进行了硬编码,因此您无需在output()
中动态分配新的学生数组,只需对原始数组中已有的指针进行排序:
void output(struct student* students)
{
/*array for sorting*/
struct student* sd[10];
struct student *stud;
/*sort students*/
for (int x = 0; x < 10; ++x)
{
stud = &students[x];
printf("id = %d\tscore = %d\n", stud->id, stud->score);
sd[stud->id] = stud;
}
/*output sorted students*/
for (int x = 0; x < 10; ++x)
{
stud = sd[x];
printf("id = %d\tscore = %d\n", stud->id, stud->score);
}
}
更新:既然您已经展示了更多代码,那么您仍然会在指针中犯下一些重大错误。正如您所展示的那样,您的代码甚至不应该编译。试试这个:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <assert.h>
static const int numStudents = 10;
struct student
{
int id;
int score;
};
struct student* allocate()
{
/*Allocate memory for ten students*/
struct student *s = malloc(numStudents * sizeof(struct student));
assert(s != 0);
/*return the pointer*/
return s;
}
void generate(struct student* students)
{
/*Generate random ID and scores for ten students, ID being between 1 and 10, scores between 0 and 100*/
int id[numStudents];
int y;
struct student* stud;
for (int i = 0; i < numStudents; i++)
{
do
{
y = rand() % size + 1;
}
while (dupe(id, i, y) != 0);
id[i] = y;
}
for (int j = 0; j < numStudents; j++)
{
stud = &students[j];
stud->id = id[j];
stud->score = rand() % 101;
}
}
int dupe(int id[], int size, int i)
{
for (int x = 0; x < size; x++)
{
if (id[x] == i)
return 1;
}
return 0;
}
void output(struct student* students)
{
/*Output information about the students in the format:
ID1 Score1
ID2 score2
ID3 score3
...
ID10 score10*/
struct student* stud;
for(int x = 0; x < numStudents; x++)
{
stud = &students[x];
printf("ID: %d\tScore: %d\n", stud->id, stud->score);
}
}
void sort(struct student* students)
{
struct student *sd = allocate();
struct student *stud;
for(int i = 0; i < numStudents; i++)
{
stud = &students[i];
sd[stud->id - 1] = *stud;
}
for(int x = 0; x < numStudents; x++)
{
stud = &sd[x];
students[x] = *stud;
}
deallocate(sd);
}
void summary(struct student* students)
{
/*Compute and print the minimum, maximum and average scores of the ten students*/
}
void deallocate(struct student* stud)
{
/*Deallocate memory from stud*/
free(stud);
}
int main()
{
/*seed random number generator*/
srand(time(NULL));
struct student* stud = NULL;
const char* c = "------------------------------\n";
/*allocate students and generate info*/
stud = allocate();
generate(stud);
output(stud);
printf("%s", c);
/*sort students*/
sort(students);
output(stud);
printf("%s", c);
/*display summary*/
summary(stud);
/*deallocate students*/
deallocate(stud);
return 0;
}
答案 2 :(得分:0)
本声明
students = &students[x];
修改传入的参数。你已经失去了'学生'指出的东西,这是struct student []
的开始。
删除此语句并尝试再次运行程序。
还有其他错误,但这应该让你失败。
指针很难。