Question

由于我的所有其他消息都是JSON，我以为我会将我的android解决方案转换为使用JSON多部分消息将相机拍摄的图像发送到WCF服务。我想我有发送工作，但不知道如何反序列化。我没有base64编码的原因是我希望android 2.1工作并且base64编码不起作用（至少这是我读过的，而且我发现的唯一“hack”只适用于小文件）。

所以在android中我尝试发送图像：

public void upload() throws Exception {
    //Url of the server
    String url = "http://192.168.0.10:8000/service/UploadImage";
    HttpClient client = new DefaultHttpClient();
    HttpPost post = new HttpPost(url);
    MultipartEntity mpEntity = new MultipartEntity();
    //Path of the file to be uploaded
    String filepath = path;
    File file = new File(filepath);
    ContentBody cbFile = new FileBody(file, "image/jpeg");     

    //Add the data to the multipart entity
    mpEntity.addPart("image", cbFile);
    post.setEntity(mpEntity);
    //Execute the post request
    HttpResponse response1 = client.execute(post);
    //Get the response from the server
    HttpEntity resEntity = response1.getEntity();
    String Response=EntityUtils.toString(resEntity);
    Log.d("Response:", Response);

    client.getConnectionManager().shutdown();
}

wcf（就像我使用来自android的httpurlconnect和outputstream发送的那样）代码。它正在工作：D：

public string UploadImage(Stream image)
    {
        var buf = new byte[1024];
        var path = Path.Combine(@"c:\tempdirectory\", "test.jpg");
        int len = 0;
        using (var fs = File.Create(path))
        {
            while ((len = image.Read(buf, 0, buf.Length)) > 0)
            {
                fs.Write(buf, 0, len);
            }
        }
        return "hej";
    }

wcf的接口 [OperationContract的] [WebInvoke（方法=“POST”， UriTemplate =“/ UploadImage”，ResponseFormat = WebMessageFormat.Json， RequestFormat = WebMessageFormat.Json）] string UploadImage（Stream image）;

如果重要，运行wcf的控制台应用程序

   static void Main(string[] args)
    {
        string baseAddress = "http://192.168.0.10:8000/Service";
        ServiceHost host = new ServiceHost(typeof(ImageUploadService), new Uri(baseAddress));
        WebHttpBinding binding = new WebHttpBinding();
        binding.MaxReceivedMessageSize = 4194304;

        host.AddServiceEndpoint(typeof(IImageUploadService),binding , "").Behaviors.Add(new WebHttpBehavior());
        host.Open();
        Console.WriteLine("Host opened");
        Console.ReadKey(true);
    }

现在问题是，我该如何解析崩溃的JSON流？有没有更好的方法呢？

注意：我尝试设置小提琴手，但是在3小时后甚至没有看到流量，我就给了它。

有没有一种实际调试此代码的好方法？

如果我将流转换为字节数组并将其保存到file：

，则忘记包含结果

--IZZI8NmDZ-Id7DWP5z0nuPPZspVAGglcfEY9
    Content-Disposition: form-data; name="image"; filename="mypicture.jpg"
    Content-Type: image/jpeg
    Content-Transfer-Encoding: binary

   ÿØÿá°Exif and other funny letters of cause :D ending with
   --IZZI8NmDZ-Id7DWP5z0nuPPZspVAGglcfEY9--

使用一些新代码我可以设法得到这个

--crdEqve1GThGGKugB3On0tGNy5h2u746
Content-Disposition: form-data; name="entity"

{"filename":"mypicture.jpg"}
--crdEqve1GThGGKugB3On0tGNy5h2u746
Content-Disposition: form-data; name="file"; filename="mypicture.jpg"
Content-Type: application/octet-stream

ÿØÿá´Exif and the whole image here ...

新的更新例程如下所示：

public void uploadFile() {
         String filepath = path;
            File file = new File(filepath);
        HttpClient httpClient = new DefaultHttpClient();

        HttpPost postRequest = new HttpPost("http://192.168.0.10:8000/service/UploadImage");
        ResponseHandler<String> responseHandler = new BasicResponseHandler();

        // Indicate that this information comes in parts (text and file)
        MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);

        try {

            //Create a JSON object to be used in the StringBody
            JSONObject jsonObj = new JSONObject();

            //Add some values
            jsonObj.put("filename", file.getName());

            //Add the JSON "part"
            reqEntity.addPart("entity", new StringBody(jsonObj.toString()));
        }
        catch (JSONException e) {
            Log.v("App", e.getMessage());
        }
        catch (UnsupportedEncodingException e) {
            Log.v("App", e.getMessage());
        }

        FileBody fileBody = new FileBody(file);//, "application/octet-stream");
            reqEntity.addPart("file", fileBody);

            try {
                postRequest.setEntity(reqEntity);

                 //Execute the request "POST"
            HttpResponse httpResp = httpClient.execute(postRequest);

            //Check the status code, in this case "created"
            if(((HttpResponse) httpResp).getStatusLine().getStatusCode() == HttpStatus.SC_CREATED){
                Log.v("App","Created");
            }
            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
    }

我仍然需要一种方法来分离流的不同部分，这样我就可以划分json消息部分（如果我需要那些），然后将图像的bytearray作为一个单独的部分来存储。我想我可以跳过json并回到原来的JUST发送图像的bytearray，但是我还是需要能够处理JSON消息。

感谢您的评论到目前为止。

Answer 1

我的第一个想法是它不是JSON流。它可能是一个字节流。此外，如果您的图像大于1024字节，您将无限读取和写入前1024个字节。您应该有一个偏移量变量，用于跟踪您已阅读的内容并在此之后开始阅读。

使用JSON和MultipartEntity将图像从Android发送到WCF

1 个答案: