Question

我制作了MSSQL查询，用于计算过去30天内的唯一IP地址和总IP记录。

SELECT count(IPAddress) AS totalPageHits, count(DISTINCT IPAddress) AS totalVisitors, count(DateTime)
FROM recordTable
WHERE DateTime > GETDATE()-30

现在我很难计算每日平均点击次数和平均每日唯一身份访问者数量。我曾尝试使用AVG，但它给出了一条错误消息“操作数据类型varchar对avg运算符无效”。
非常感谢任何帮助。

Answer 1

SELECT  AVG(HitCount) as AverageHits,
    AVG(UniqueHitCount) As AverageUniqueHits
FROM
(
SELECT  COUNT(IPAddress) as HitCount,
        COUNT(DISTINCT IPAddress) as UniqueHitCount,
        DATEDIFF(d, GETDATE(), DateTime) as Day
FROM tblHitCounter
WHERE DateTime > GETDATE() - 30
GROUP BY DATEDIFF(d, GETDATE(), DateTime)
) sub

Answer 2

您需要按天分组，然后执行平均值：

select avg(totalPageHits) as avgDailyTotalPageHits,
       avg(totalVisitors) as avgDailyTotalVisitors
from (SELECT cast(DateTime as date) as thedate,
             count(IPAddress) AS totalPageHits,
             count(DISTINCT IPAddress) AS totalVisitors, count(DateTime) as cnt
      FROM recordTable
      WHERE DateTime > GETDATE()-30
      group by cast(DateTime as date)
     ) t

MS SQL查询计算平均每月唯一身份访问者

2 个答案: