考虑以下查询,其中聚合在两个表中发生:Sales和Promo以及聚合值再次用于计算。
SELECT
sales.article_id,
avg((sales.euro_value - ZEROIFNULL(promo.euro_value)) / NULLIFZERO(sales.qty - ZEROIFNULL(promo.qty)))
FROM
( SELECT
sales.article_id,
sum(sales.euro_value),
sum(sales.qty)
from SALES_TABLE sales
where year >= 2011
group by article_id
) sales
LEFT OUTER JOIN
( SELECT
promo.article_id,
sum(promo.euro_value),
sum(promo.qty)
from PROMOTION_TABLE promo
where year >= 2011
group by article_id
) promo
ON sales.article_id = promo.article_id
GROUP BY sales.article_id;
有关查询的一些注释:
那么,您能否建议一种更好的方式来编写此查询。感谢您阅读此内容:)
答案 0 :(得分:2)
不确定avg功能是如何进入混音的,所以我将其删除。
SELECT article_id,
(SUM(sales_value) - SUM(promo_value)) /
(SUM(sales_qty) - SUM(promo_qty))
FROM (
SELECT
article_id,
sum(euro_value) AS sales_value,
sum(qty) AS sales_qty,
0 AS promo_value,
0 AS promo_qty
from SALES_TABLE sales
where year >= 2011
group by article_id
UNION ALL
SELECT
article_id,
0 AS sales_value,
0 AS sales_qty,
sum(euro_value) AS promo_value,
sum(qty) AS promo_qty
from SALES_TABLE sales
where year >= 2011
group by article_id
) AS comb
GROUP BY article_id;