Question

我想创建一个容器服务，所以我使用了带有构造函数的classe：

service.xml：

<container xmlns="http://symfony.com/schema/dic/services"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://symfony.com/schema/dic/services http://symfony.com/schema/dic/services/services-1.0.xsd">

<parameters>
    <parameter key="myapp_mybundle.locationmanager.class">My_app\MyBundle\Manager\LocationManager</parameter>
    <parameter key="myapp_mybundle.rootLocation">rootLocation</parameter>
</parameters>

<services>
    <service id="myapp_mybundle.locationmanager" class="%myapp_mybundle.locationmanager.class%">
    <argument>%myapp_mybundle.rootLocation%</argument>

    </service>
</services>

MyappMyBundleExtension.php

$container->set('myapp_mybundle.locationmanager', $manager);

class locationManager：

class LocationManager
{
     /**
     * @var Location
     */
protected $rootLocation;

public function __construct(Location $rootLocation)
{
    $this->rootLocation = $rootLocation;
}
   .....

和控制器中的一些动作：

   $locationManager =  $this->container->get("myapp_mybundle.locationmanager");

我收到此错误：

  You have requested a non-existent service "myapp_mybundle.locationmanager".

Answer 1

您的服务没有大写“b”......应该是

$locationManager = $this->container->get("myapp_mybundle.locationmanager");

Answer 2

您实际加载了services.xml文件吗？

像这样：

use Symfony\Component\DependencyInjection\Loader\XmlFileLoader;
use Symfony\Component\Config\FileLocator;

public function load(array $configs, ContainerBuilder $container)
{
    $loader = new XmlFileLoader($container, new FileLocator(__DIR__.'/../Resources/config'));
    $loader->load('services.xml');
}

如果您不这样做，您的服务不会注入容器，您将无法加载它们。

有关此内容的更多信息，请访问here和here。

Symfony2中的服务

2 个答案: