我正在尝试使用googlemaps地理编码器检索地址..但我只获得了几个地址..我看到我的javascript无法在10个地址后检索..我是我的代码
function fetchData(lat,lng,type){
$('#placedata').empty();
myLatlng = new google.maps.LatLng(parseFloat(lat), parseFloat(lng));
map = new google.maps.Map(document.getElementById('map'), {
mapTypeId: google.maps.MapTypeId.ROADMAP,
center: myLatlng,
zoom: 10});
var request = {location: myLatlng,radius: 50000,types: [type]};
var service = new google.maps.places.PlacesService(map);
service.search(request, callback);
}
function callback(results, status) {
for (var i = 0; i < results.length; i++) {
if (status == google.maps.places.PlacesServiceStatus.OK) {
createMarker(results[i]);
}
}
}
function createMarker(place) {
place.geometry.location});
var request = {reference: place.reference,};
service = new google.maps.places.PlacesService(map);
service.getDetails(request, detailsDisplay);
function detailsDisplay(details, status) {
$('#placedata').append('<tr><td><a href='+details.url+'>'+details.name+'</a></td></tr>');
}
}
因为我看到很多人有同样的问题..有一种方法或使用setTimeout函数并延迟请求所以我得到至少20个地址..任何帮助将不胜感激..thankyou
答案 0 :(得分:4)
解决方案是使用setTimeout
来阻止OVER_QUERY_LIMIT
:
function createMarker(place) {
//var placeLoc = place.geometry.location;
//var marker = new google.maps.Marker({map: map,zIndex: 100,position: place.geometry.location});
var request = {
reference : place.reference,
};
service = new google.maps.places.PlacesService(map);
service.getDetails(request, function(details, status) {
if (status === google.maps.places.PlacesServiceStatus.OK) {
$('#placedata').append('<tr><td><a href='+details.url+'>' + details.name + '</a></td></tr>');
} else if (status === google.maps.GeocoderStatus.OVER_QUERY_LIMIT) {
setTimeout(function() {
createMarker(place);
}, 200);
}
});
}
答案 1 :(得分:-1)
我有解决方案。
试试这个
if(pagination.hasNextPage){
pagination.nextPage();
}
if(pagination.b == null){
createMarker(place);
}
//不需要setTimeout。试试这个。它会对你有所帮助。