Question

如何创建一个记录两个不同团队之间胜负的方法？这是团队对象＆amp;构造

public class NFLTeam4
{   private int win;
    private int loss;
    private String team;

public NFLTeam4(String teamName)
{   win = 0;
    loss = 0;
    team = teamName;
}
public NFLTeam4(int w, int l)
{   win = w;
    loss = l;
}
}

这是我尝试创造一种胜利的游戏方法。

public class NFLGameDay4{
   public static void main(String[] args){  
    NFLTeam4 falcons = new NFLTeam4("Falcons");
    NFLTeam4 chiefs = new NFLTeam4("Chiefs");
    NFLTeam4 jets = new NFLTeam4("Jets");
}       

public NFLTeam4 winAGame(NFLTeam4 b)
{   int win = 1;
    int loss = 0;
    return new NFLTeam4(win, loss);
}

Answer 1

首先，您的NFLTeam4课程似乎能够代表团队......

public NFLTeam4(String teamName) {   
    win = 0;
    loss = 0;
    team = teamName;
}

......或团队的记录......

public NFLTeam4(int w, int l) {   
    win = w;
    loss = l;
}

但不是两者：没有办法预先提供团队名称，然后再修改记录。要纠正这一点（从而使管理团队的记录成为可能），请考虑删除第二个构造函数（int w, int l）并创建两个方法来处理为您更改记录：

public void addWin() { 
    ++win;
}

//similar code for addLoss

请注意，您可能希望添加getWinCount之类的方法。您要添加的内容以及编码方式取决于您，这只是为了让您入门。

现在winAGame只需要在提供的小组addWin）上调用NFLTeam4 b。

Answer 2

您可以在Map课程中创建结果NFLTeam4。

public class NFLTeam4
{
  private enum RESULT { WIN, LOSS };
  private Map<RESULT, List<NFLTeam4>> results = new HashMap<RESULT, ArrayList<NFLTeam4>>;
  // you can leave the constructor and other variables as they are

  public void winAGame(NFLTeam4 b) {
    win = win + 1;
    // Now check and add to your results map 
    // you will need to make sure your map is initialised properly
    results.get(RESULT.WIN).add(b);
  }
}

您正在封装NFLTeam4对象中赢或输游戏的行为。您还可以扩展RESULT枚举，以包含有关结果的日期，游戏编号，地点等的一些信息。

这只是一个关于如何运作的说明。您应该根据要求考虑如何设计对象。

在两个不同的团队之间创建一个赢/输记录方法

2 个答案: