我有一张桌子
create table us
(
a number
);
现在我有以下数据:
a
1
2
3
4
null
null
null
8
9
现在我需要一个查询来计算列a中的空和非空值
答案 0 :(得分:199)
这适用于Oracle和SQL Server(您可以将其用于另一个RDBMS):
select sum(case when a is null then 1 else 0 end) count_nulls
, count(a) count_not_nulls
from us;
或者:
select count(*) - count(a), count(a) from us;
答案 1 :(得分:52)
如果我理解正确,你想要计算列中的所有NULL和所有NOT NULL ......
如果这是正确的:
SELECT count(*) FROM us WHERE a IS NULL
UNION ALL
SELECT count(*) FROM us WHERE a IS NOT NULL
在阅读评论后编辑完整查询:]
SELECT COUNT(*), 'null_tally' AS narrative
FROM us
WHERE a IS NULL
UNION
SELECT COUNT(*), 'not_null_tally' AS narrative
FROM us
WHERE a IS NOT NULL;
答案 2 :(得分:38)
这是一个适用于Oracle的快速且脏的版本:
select sum(case a when null then 1 else 0) "Null values",
sum(case a when null then 0 else 1) "Non-null values"
from us
答案 3 :(得分:19)
我理解你的查询,你只需运行这个脚本并获得Total Null,Total NotNull行,
select count(*) - count(a) as 'Null', count(a) as 'Not Null' from us;
答案 4 :(得分:14)
通常我会使用这个技巧
select sum(case when a is null then 0 else 1 end) as count_notnull,
sum(case when a is null then 1 else 0 end) as count_null
from tab
group by a
答案 5 :(得分:6)
表示非空值
select count(a)
from us
表示空值
select count(*)
from us
minus
select count(a)
from us
因此
SELECT COUNT(A) NOT_NULLS
FROM US
UNION
SELECT COUNT(*) - COUNT(A) NULLS
FROM US
应该做的工作
更好的是,列标题正确无误。
SELECT COUNT(A) NOT_NULL, COUNT(*) - COUNT(A) NULLS
FROM US
在我的系统上进行的某些测试中,需要进行全表扫描。
答案 6 :(得分:5)
这有点棘手。假设表只有一列,则Count(1)和Count(*)将给出不同的值。
set nocount on
declare @table1 table (empid int)
insert @table1 values (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(NULL),(11),(12),(NULL),(13),(14);
select * from @table1
select COUNT(1) as "COUNT(1)" from @table1
select COUNT(empid) "Count(empid)" from @table1
正如您在图像中看到的那样,第一个结果显示该表有16行。其中两行为NULL。因此,当我们使用 Count(*)时,查询引擎计算行数,因此我们将计数结果计为16.但是在 Count(empid)的情况下,它计算了列 empid 中的非NULL值。所以我们得到了14的结果。
所以每当我们使用COUNT(Column)时,请确保我们处理NULL值,如下所示。
select COUNT(isnull(empid,1)) from @table1
将计算NULL和非NULL值。
注意:即使表格由多个列组成,也同样适用。 Count(1)将给出总行数,而不管NULL /非NULL值。只有当使用Count(Column)计算列值时,我们才需要处理NULL值。
答案 7 :(得分:4)
仅提供另一种选择,Postgres 9.4 + allows applying a FILTER
to aggregates:
SELECT
COUNT(*) FILTER (WHERE a IS NULL) count_nulls,
COUNT(*) FILTER (WHERE a IS NOT NULL) count_not_nulls
FROM us;
SQLFiddle:http://sqlfiddle.com/#!17/80a24/5
答案 8 :(得分:3)
我遇到了类似的问题:计算所有不同的值,将空值计算为1。在这种情况下,简单计数不起作用,因为它不考虑空值。
这是一个适用于SQL的代码片段,不涉及选择新值。 基本上,一旦执行了distinct,也使用row_number()函数返回新列(n)中的行号,然后对该列执行计数:
SELECT COUNT(n)
FROM (
SELECT *, row_number() OVER (ORDER BY [MyColumn] ASC) n
FROM (
SELECT DISTINCT [MyColumn]
FROM [MyTable]
) items
) distinctItems
答案 9 :(得分:2)
尝试
SELECT
SUM(ISNULL(a)) AS all_null,
SUM(!ISNULL(a)) AS all_not_null
FROM us;
简单!
答案 10 :(得分:2)
尝试一下。
SELECT CASE
WHEN a IS NULL THEN 'Null'
ELSE 'Not Null'
END a,
Count(1)
FROM us
GROUP BY CASE
WHEN a IS NULL THEN 'Null'
ELSE 'Not Null'
END
答案 11 :(得分:2)
以下是两个解决方案:
Select count(columnname) as countofNotNulls, count(isnull(columnname,1))-count(columnname) AS Countofnulls from table name
OR
Select count(columnname) as countofNotNulls, count(*)-count(columnname) AS Countofnulls from table name
答案 12 :(得分:2)
使用ISNULL嵌入式功能。
答案 13 :(得分:2)
如果您正在使用MS Sql Server ...
SELECT COUNT(0) AS 'Null_ColumnA_Records',
(
SELECT COUNT(0)
FROM your_table
WHERE ColumnA IS NOT NULL
) AS 'NOT_Null_ColumnA_Records'
FROM your_table
WHERE ColumnA IS NULL;
我不建议你这样做......但是你在这里(与结果在同一张表中)
答案 14 :(得分:1)
select count(isnull(NullableColumn,-1))
答案 15 :(得分:1)
这适用于T-SQL。如果您只计算某些内容并且想要包含空值,请使用COALESCE而不是大小写。
IF OBJECT_ID('tempdb..#us') IS NOT NULL
DROP TABLE #us
CREATE TABLE #us
(
a INT NULL
);
INSERT INTO #us VALUES (1),(2),(3),(4),(NULL),(NULL),(NULL),(8),(9)
SELECT * FROM #us
SELECT CASE WHEN a IS NULL THEN 'NULL' ELSE 'NON-NULL' END AS 'NULL?',
COUNT(CASE WHEN a IS NULL THEN 'NULL' ELSE 'NON-NULL' END) AS 'Count'
FROM #us
GROUP BY CASE WHEN a IS NULL THEN 'NULL' ELSE 'NON-NULL' END
SELECT COALESCE(CAST(a AS NVARCHAR),'NULL') AS a,
COUNT(COALESCE(CAST(a AS NVARCHAR),'NULL')) AS 'Count'
FROM #us
GROUP BY COALESCE(CAST(a AS NVARCHAR),'NULL')
答案 16 :(得分:1)
建立了Alberto,我添加了汇总。
SELECT [Narrative] = CASE
WHEN [Narrative] IS NULL THEN 'count_total' ELSE [Narrative] END
,[Count]=SUM([Count]) FROM (SELECT COUNT(*) [Count], 'count_nulls' AS [Narrative]
FROM [CrmDW].[CRM].[User]
WHERE [EmployeeID] IS NULL
UNION
SELECT COUNT(*), 'count_not_nulls ' AS narrative
FROM [CrmDW].[CRM].[User]
WHERE [EmployeeID] IS NOT NULL) S
GROUP BY [Narrative] WITH CUBE;
答案 17 :(得分:1)
SELECT SUM(NULLs) AS 'NULLS', SUM(NOTNULLs) AS 'NOTNULLs' FROM
(select count(*) AS 'NULLs', 0 as 'NOTNULLs' FROM us WHERE a is null
UNION select 0 as 'NULLs', count(*) AS 'NOTNULLs' FROM us WHERE a is not null) AS x
这很难,但它会返回一条带有2个cols的记录,表示空值与非空值的计数。
答案 18 :(得分:1)
SELECT
ALL_VALUES
,COUNT(ALL_VALUES)
FROM(
SELECT
NVL2(A,'NOT NULL','NULL') AS ALL_VALUES
,NVL(A,0)
FROM US
)
GROUP BY ALL_VALUES
答案 19 :(得分:1)
所有答案都是错误的或过时的。
执行此查询的简单正确的方法是使用COUNT_IF
函数。
SELECT
COUNT_IF(a IS NULL) AS nulls,
COUNT_IF(a IS NOT NULL) AS not_nulls
FROM
us
答案 20 :(得分:1)
如果是mysql,你可以试试这样的东西。
select
(select count(*) from TABLENAME WHERE a = 'null') as total_null,
(select count(*) from TABLENAME WHERE a != 'null') as total_not_null
FROM TABLENAME
答案 21 :(得分:1)
我在postgres 10中创建了表,并且以下两项均有效:
select count(*) from us
和
select count(a is null) from us
答案 22 :(得分:0)
用于计算非空值
select count(*) from us where a is not null;
用于计算空值
select count(*) from us where a is null;
答案 23 :(得分:0)
以防万一你想要一个记录:
select
(select count(*) from tbl where colName is null) Nulls,
(select count(*) from tbl where colName is not null) NonNulls
- )
答案 24 :(得分:0)
就我而言,我希望在多个列之间使用“ 空分布”:
case 'MODIFIED_GROUPS':
return { ...state, arrayGroups: action.payload }
根据'...',它可以轻松扩展到更多列,并根据需要扩展
答案 25 :(得分:-1)
a为null的元素数:
select count(a) from us where a is null;
a不为null的元素数:
select count(a) from us where a is not null;