使用GAE数据存储区进行身份验证会在实体用户上返回null

时间:2012-10-03 22:49:55

标签: java google-app-engine google-cloud-datastore

我正在尝试创建自己的身份验证。每次我尝试登录,并且在GAE数据存储区中找不到用户名时,我都会获得INTERNAL_SERVER_ERROR。

它说:

java.lang.NullPointerException
at com.pawnsoftware.User.authenticate(User.java:16)
at com.pawnsoftware.UserLoginServlet.doPost(UserLoginServlet.java:24)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:637)

依旧......

如何避免出现此错误?

该错误出现在:

if (user==null) {
    message = "Username not found.";
}

验证用户:

public static String authenticate(String username, String password) {
    String message;
    Entity user = UserUtil.findUserEntity(username);
    String pass = user.getProperty("password").toString();
    if (user==null) {
        message = "Username not found.";
    } else if (user!=null && !password.equals(pass)) {
        message = "Password is incorrect.";
    } else if (user!=null && password.equals(pass)) {
        message = "Successfully logged in!";
    } else {
        message = "Sorry, cannot find the username and password.";
    } 
    return message;
}

查找用户实体:

public static Entity findUserEntity (String username) {
    Key userKey = KeyFactory.createKey("User", username);
    try {
      return datastore.get(userKey);
    } catch (EntityNotFoundException e) {
      return null;
    }
}

身份验证更新:

public static String authenticate(String username, String password) {
    String message;
    Entity user = UserUtil.findUserEntity(username);
    password = encrypt(password);
    String pass = "";   
        try {
            pass = user.getProperty("password").toString();
        } catch (NullPointerException e) {
            message = "Username not found.";
        }
    if (user==null) {
        message = "Username not found.";
    } else if (user!=null && !password.equals(pass)) {
        message = "Password is incorrect.";
    } else if (user!=null && password.equals(pass)) {
        message = "Successfully logged in!";
    } else {
        message = "Sorry, cannot find the username and password.";
    } 
    return message;
}

2 个答案:

答案 0 :(得分:0)

如果use为null,则此行将失败:

String pass = user.getProperty("password").toString();

答案 1 :(得分:0)

如果您获得EntityNotFoundException并返回null,则不会显示。反过来,这可能会导致变量NullPointerException的{​​{1}}:

user

你可以在这里添加一个警卫声明:

user.getProperty("password").toString();