我正在尝试将自由格式日期字符串解析为有意义的日期。到目前为止,我已经提出了这个功能:
"""Parse raw date string into YYYY-MM-DD"""
def __parseDate(self, rawDate):
if len(rawDate) == 0:
return u""
if "{{Birth year and age|" in rawDate:
rawDate = rawDate.replace("{{","").replace("}}","")
year = rawDate.split("|")[1].strip()
return year + "-01-01"
elif "{{Birth date and age|" in rawDate:
rawDate = rawDate.replace("{{","").replace("}}","")
year = rawDate.split("|")[1].strip()
month = rawDate.split("|")[2].strip()
day = rawDate.split("|")[3].strip()
if len(month) == 1:
month = "0" + month
if len(day) == 1:
day = "0" + day
return year + "-" + month + "-" + day
elif "{{" in rawDate:
self.__log(u"XXX Date parse error (unknown template): " + rawDate)
return u"1770-01-01"
elif re.match("([a-zA-Z]* [0-9][0-9]?, [0-9][0-9][0-9][0-9])", rawDate):
match = re.findall("([a-zA-Z]* [0-9][0-9]?, [0-9][0-9][0-9][0-9])", rawDate)[0]
parts = match.replace(",","").split(" ")
year = parts[2].strip()
month = parts[0].replace(".","").strip()
day = parts[1].strip()
tryAgain = False
try:
month = str(strptime(month,'%B').tm_mon)
except:
tryAgain = True
pass
try:
if tryAgain:
month = str(strptime(month,'%b').tm_mon)
except:
self.__log(u"XXX Date parse error: " + rawDate)
return u"1770-01-01"
pass
if len(month) == 1:
month = "0" + month
if len(day) == 1:
day = "0" + day
return year + "-" + month + "-" + day
elif re.match("[0-9][0-9][0-9][0-9]-[0-9][0-9]?-[0-9][0-9]?", rawDate):
parts = rawDate.split("-")
year = parts[0].strip()
month = parts[1].strip()
day = parts[2].strip()
if len(month) == 1:
month = "0" + month
if len(day) == 1:
day = "0" + day
return year + "-" + month + "-" + day
else:
self.__log(u"XXX Date parse error: " + rawDate)
return u"1770-01-01"
我是在正确的轨道上还是有更好的方法?
更新通过自由格式字符串,我的意思是来自维基页面,特别是人员数据模板。此模板中的日期字段是自由格式,因为人类已在其中键入内容。通常,这是任意数量格式的日期,或者它本身是描述日期的另一个wiki模板。以下是该领域可能存在的一些例子:
{{Birth year and age|1933}}
August 23, 1967
1990-01-29
23 August 1967
1999
a;lsdfhals;djkfh