命令行参数 - 所需对象:'objshell.NameSpace(...)'

时间:2012-10-03 17:29:00

标签: object vbscript namespaces

我正在开发一个脚本,该脚本将利用Windows的内置功能解压缩提供的.zip文件。我是vbscript的新手,所以一些语法让我有点困惑。我正在使用一些现有代码并尝试修改它,以便它将采用文件名的命令行选项。 如果我使用命令行传递文件名,我收到错误:

  

需要的对象:'objshell.NameSpace(...)'

如果我在脚本中使用文本填充相同的变量,则脚本将无错运行。在尝试使用命令参数时是否还有其他一些内容?

这是我的代码:

Option Explicit

Dim sDestinationDirectory,sLogDestination,fso,outLog,sJunk,sSourceFile

sDestinationDirectory = "C:\scripts\vbscriptTemplates\unzip"
sLogDestination = "C:\scripts\vbscriptTemplates\"

Set fso=CreateObject("Scripting.FileSystemObject")
Set outLog = fso.OpenTextFile("unzipRIP.log", 2, True)
If WScript.Arguments.Count = 1 Then
    sSourceFile = WScript.Arguments.Item(0)     'Using this line the code will fail.
    'sSourceFile = "C:\scripts\vbscriptTemplates\test.zip"     'Using this line the code will run.
    outLog.WriteLine ".:|Processing new zip file|:."
    outLog.WriteLine "Processing file: " & sSourceFile
    Extract sSourceFile,sDestinationDirectory
Else
    sJunk = MsgBox("File to be processed could not be found. Please verify.",0,"Unzip - File not found")
    outLog.WriteLine "File to be processed could not be found. Please verify."
    outLog.Close
    Wscript.Quit
End If

Sub Extract( ByVal myZipFile, ByVal myTargetDir )
    Dim intOptions, objShell, objSource, objTarget

    outLog.WriteLine "Processing file in subroutine: " & myZipFile & " target " & myTargetDir
    ' Create the required Shell objects
    Set objShell = CreateObject( "Shell.Application" )

    ' Create a reference to the files and folders in the ZIP file
    Set objSource = objShell.NameSpace( myZipFile ).Items()

    ' Create a reference to the target folder
    Set objTarget = objShell.NameSpace( myTargetDir )
    intOptions = 4

    ' UnZIP the files
    objTarget.CopyHere objSource, intOptions

    ' Release the objects
    Set objSource = Nothing
    Set objTarget = Nothing
    Set objShell  = Nothing
End Sub

引用的行是

  

sSourceFile = WScript.Arguments.Item(0)

这是我尝试对Rob van der Woude编写的代码进行修改。 http://www.robvanderwoude.com/vbstech_files_zip.php#CopyHereUNZIP

1 个答案:

答案 0 :(得分:12)

尝试

Set fso = CreateObject("Scripting.FileSystemObject")
sSourceFile = fso.GetAbsolutePathName(WScript.Arguments.Item(0))

而不是

sSourceFile = WScript.Arguments.Item(0)