Question

我是Flex新手，也是编写Web服务客户端的新手。我的问题更多是关于Flex（Flash Builder 4.5）API，使用什么API。

我想访问一个Web服务，并为它创建一个Flex / AIRwrapper，任何人都可以使用。

我必须在POST https://build.phonegap.com/api/v1/apps
内容类型必须是“multipart / form-data”

请求的JSON主体应该具有“数据”的名称，并且将是这样的：

data={"title":"API V1 App","package":"com.alunny.apiv1","version":"0.1.0","create_method":"file"}

在帖子的多部分正文中包含一个zip文件，参数名称为“file”。

我想创建一个'multipart / form-data'帖子并发送一个字符串和一个zip文件。

我对自己的第一个问题是，如果我在体内发送两个字符串+二进制数据，服务器将如何理解字符串结尾和zip文件的起始位置？

然后我读了text + binary data can be sent through "multipart/form-data" post request的原因。必须有一些界限。

在此之后，我在flex中阅读和示例并尝试遵循它。 http://codeio.wordpress.com/2010/04/03/5-minutes-on-adobe-flex-mimic-file-upload-for-in-memory-contents/ 但它似乎对我不起作用。

    public function createNewApp(cb:Function , appFile : File):void 
    {
        var service:HTTPService = new HTTPService();
        service.url = ROOT+"apps";
        service.showBusyCursor = true;
        service.addEventListener(ResultEvent.RESULT, function(e:ResultEvent):void {
            //translate JSON
            trace(e.result);
            var result:String = e.result.toString();
            var data:Object = JSON.parse(result);               
            cb(data.link);
        });
        service.addEventListener(FaultEvent.FAULT, defaultFaultHandler); //todo : allow user to add his own as well
        authAndUploadNewApp(service,appFile);
    }

    private function authAndUploadNewApp(service:HTTPService,appFile : File):void {

        var encoder:Base64Encoder = new Base64Encoder();
        encoder.encode(username + ":"+password);
        service.headers = {Accept:"application/json", Authorization:"Basic " + encoder.toString()};
        service.method ="POST";
        var boundary:String = UIDUtil.createUID();
        service.contentType = "multipart/form-data; boundary=—————————" + boundary;
        var stream:FileStream = new FileStream();
        stream.open(appFile, FileMode.READ);
        var binaryData:ByteArray = new ByteArray();             
        var fileData : String = new String();
        stream.readBytes(binaryData);
        stream.close();         
        fileData = binaryData.readUTFBytes(binaryData.bytesAvailable); // I think this is where I have problem.... how do 
                   //how do i converrt this bytearray/stream of data to string and send it in my post request's body - i guess if this step work rest should work..   
        var params: String = new String();
        var content:String = "—————————" + boundary + "nr";
        content += 'Content-Disposition: form-data; name="data";' + '{"title":"ELS test app 2","package":"com.elsapp.captivate","version":"12.3.09","create_method":"file"}' + "nr";
        content += "—————————" + boundary + "nr";
        content += 'Content-Disposition: form-data; name="file";' + fileData  + "nr";
        content += "—————————–" + boundary + "–nr";
        service.request = content;
        service.send();
    }

Multipart / form-data Flex HTTPService上传文件

0 个答案: