Question

是否有来自QtSingleApplication的C ++类Qt Solutions的Python版本？

QtSingleApplication用于确保永远不会有多个应用程序实例同时运行。

Answer 1

这是我自己的实现。它已经过Python 2.7和PySide 1.1的测试。

它与C++ version of QtSingleApplication具有基本相同的界面。主要区别在于您必须为构造函数提供应用程序唯一ID。（默认情况下，C ++版本使用可执行文件的路径作为唯一ID;这在此处不起作用，因为可执行文件很可能是python.exe。）

from PySide.QtCore import *
from PySide.QtGui import *
from PySide.QtNetwork import *

class QtSingleApplication(QApplication):

    messageReceived = Signal(unicode)

    def __init__(self, id, *argv):

        super(QtSingleApplication, self).__init__(*argv)
        self._id = id
        self._activationWindow = None
        self._activateOnMessage = False

        # Is there another instance running?
        self._outSocket = QLocalSocket()
        self._outSocket.connectToServer(self._id)
        self._isRunning = self._outSocket.waitForConnected()

        if self._isRunning:
            # Yes, there is.
            self._outStream = QTextStream(self._outSocket)
            self._outStream.setCodec('UTF-8')
        else:
            # No, there isn't.
            self._outSocket = None
            self._outStream = None
            self._inSocket = None
            self._inStream = None
            self._server = QLocalServer()
            self._server.listen(self._id)
            self._server.newConnection.connect(self._onNewConnection)

    def isRunning(self):
        return self._isRunning

    def id(self):
        return self._id

    def activationWindow(self):
        return self._activationWindow

    def setActivationWindow(self, activationWindow, activateOnMessage = True):
        self._activationWindow = activationWindow
        self._activateOnMessage = activateOnMessage

    def activateWindow(self):
        if not self._activationWindow:
            return
        self._activationWindow.setWindowState(
            self._activationWindow.windowState() & ~Qt.WindowMinimized)
        self._activationWindow.raise_()
        self._activationWindow.activateWindow()

    def sendMessage(self, msg):
        if not self._outStream:
            return False
        self._outStream << msg << '\n'
        self._outStream.flush()
        return self._outSocket.waitForBytesWritten()

    def _onNewConnection(self):
        if self._inSocket:
            self._inSocket.readyRead.disconnect(self._onReadyRead)
        self._inSocket = self._server.nextPendingConnection()
        if not self._inSocket:
            return
        self._inStream = QTextStream(self._inSocket)
        self._inStream.setCodec('UTF-8')
        self._inSocket.readyRead.connect(self._onReadyRead)
        if self._activateOnMessage:
            self.activateWindow()

    def _onReadyRead(self):
        while True:
            msg = self._inStream.readLine()
            if not msg: break
            self.messageReceived.emit(msg)

这是一个简单的测试程序：

import sys
from PySide.QtGui import *
from QtSingleApplication import QtSingleApplication

appGuid = 'F3FF80BA-BA05-4277-8063-82A6DB9245A2'
app = QtSingleApplication(appGuid, sys.argv)
if app.isRunning(): sys.exit(0)

w = QWidget()
w.show()
app.setActivationWindow(w)
sys.exit(app.exec_())

Answer 2

您可以查看此blog entry。它适用于Pyside，但我猜它也适用于PyQt4。

QtSingleApplication for PySide或PyQt

2 个答案: