我有自定义视图,并希望在该自定义视图上再添加一个自定义视图。这是我的自定义视图类:
public class CustomCircle extends View{
float radius;
Paint paint = new Paint();
String message = "";
public CustomCircle(Context context, AttributeSet attrs) {
super(context, attrs);
}
@Override
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
canvas.drawCircle(getWidth()/2, getHeight()/2,radius, paint);
}
@Override
public boolean onTouchEvent(MotionEvent event) {
boolean isClickInCircle = false;
float x = event.getX();
float y = event.getY();
double check = Math.sqrt((x-getWidth()/2)*(x-getWidth()/2) + (y-getHeight()/2)*(y-getHeight()/2));
if (check<=radius) {
isClickInCircle= true;
}
if (isClickInCircle) {
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
Toast.makeText(getContext(),message, Toast.LENGTH_LONG).show();
return true;
case MotionEvent.ACTION_UP:
Toast.makeText(getContext(), message, Toast.LENGTH_LONG).show();
return true;
default:
break;
}
}
return false;
}
并且正在使用另一个扩展LinearLayout
的类:
public class B extends LinearLayout {
private Paint paint;
public B(Context context) {
super(context);
paint = new Paint();
paint.setColor(Color.WHITE);
paint.setStyle(Style.FILL);
}
public void addCircle() {
CustomCircle circleBlue = new CustomCircle(getContext(), null);
circleBlue.paint.setColor(Color.WHITE);
circleBlue.paint.setAntiAlias(true);
circleBlue.radius = 160;
circleBlue.message = "Clicked";
addView(circleBlue);
CustomCircle circleRed = new CustomCircle(getContext(), null);
circleRed.paint.setColor(Color.RED);
circleRed.paint.setAntiAlias(true);
circleRed.radius = 80;
circleRed.message = "Clicked";
addView(circleRed);
}
我正在使用:
从主活动类调用B类@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
B root = new B(this);
root.addCircle();
setContentView(root);
}
输出显示的只是一个圆圈而不是另一个圆圈内的圆圈。我的代码出了什么问题?
答案 0 :(得分:1)
输出显示我只有一个圆而不是内圈 圈。
如果您想重叠儿童,则选择了错误的布局,RelativeLayout
或FrameLayout
是可行的方法。另外,关于你的代码:
public class B extends RelativeLayout {
//...
public void addCircle() {
// the constructor that uses the AttributeSet should be added if you use the
// custom component in the xml layout
CustomCircle circleBlue = new CustomCircle(getContext());
// ...
// add it with LayoutParams
RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(
RelativeLayout.LayoutParams.WRAP_CONTENT,
RelativeLayout.LayoutParams.WRAP_CONTENT);
rlp.addRule(RelativeLayout.CENTER_IN_PARENT);
addView(circleBlue, rlp);
// the same for the other view
}
此外,您的两个圆圈将具有相同的尺寸,因此它们将完全重叠(并且您将无法看到它们),您需要通过LayoutParams
为它们提供不同的尺寸,例如:
RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(200, 200);
表示第一个并且:
RelativeLayout.LayoutParams rlp = new RelativeLayout.LayoutParams(100, 100);
为第二个。
答案 1 :(得分:0)
布局中是否有2个圆圈,但您只能看到一个圆圈 因为它与第一个圆圈的颜色相同,并且它们相互叠加?
更改circleRed.paint.setColor(Color.WHITE);
到circleRed.paint.setColor(Color.BLACK);
并看看它给出了什么