我有一个画布,其中绘制一些GraphNodes并将它们作为ContentControls添加到画布。所有图形节点都有一个装饰器,我用它来绘制从一个节点到另一个节点的连接线。装饰者有一个方法OnMouseUp:
protected override void OnMouseUp(System.Windows.Input.MouseButtonEventArgs e)
{
var SourceNode = AdornedElement;
Point pt = PointToScreen(Mouse.GetPosition(this));
var DestinationNode = ???
}
此时我有源节点,我开始在AdornedElement中绘制线,这是最初的GraphNode。另外,我有释放鼠标的坐标。在这一点下是另一个GraphNode。如何找到这一点下的节点?
谢谢。
答案 0 :(得分:0)
好的,经过多次研究后我找到了解决方案:
protected override void OnMouseUp(System.Windows.Input.MouseButtonEventArgs e)
{
Point pt = PointToScreen(Mouse.GetPosition(this));
UIElement canvas = LogicalTreeHelper.GetParent(AdornedElement) as UIElement;
// This is important to get the mouse position relative to the canvas, otherwise it won't work
pt = canvas.PointFromScreen(pt);
VisualTreeHelper.HitTest(canvas, null, HitTestResultCallbackHandler, new PointHitTestParameters(pt));
}
然后使用HitTest方法找到GraphNode。请记住,GraphNode是一个自定义对象。
public HitTestResultBehavior HitTestResultCallbackHandler(HitTestResult result)
{
if (result != null)
{
// Search for elements that have GraphNode as parent
DependencyObject dobj = VisualTreeHelper.GetParent(result.VisualHit);
while (dobj != null && !(dobj is ContentControl))
{
dobj = VisualTreeHelper.GetParent(dobj);
}
ContentControl cc = dobj as ContentControl;
if (!ReferenceEquals(cc, null))
{
IEnumerable<DependencyObject> dependencyObjects = cc.GetSelfAndAncestors();
if (dependencyObjects.Count() > 0)
{
IEnumerable<ContentControl> contentControls = dependencyObjects.Where(x => x.GetType() == typeof(ContentControl)).Cast<ContentControl>();
if (contentControls.Count() > 0)
{
ContentControl cControl = contentControls.FirstOrDefault(x => x.Content.GetType() == typeof(GraphNode));
if (cControl != null)
{
var graphNode = cControl.Content as GraphNode;
if (!ReferenceEquals(graphNode, null))
{
// Keep the result in a local variable
m_DestinationNode = graphNode;
return HitTestResultBehavior.Stop;
}
}
}
}
}
}
m_DestinationNode = null;
return HitTestResultBehavior.Continue;
}