我有一个从db读取数据的函数。但这总是返回错误..我没有太多的知识在android..looking寻求帮助
10-03 11:33:05.870: E/AndroidRuntime(1321): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.projects.myworldsafe/com.projects.myworldsafe.DeailedView}: android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0
。
String getItemDetailsWp(String id){
System.out.print(id);
SQLiteDatabase db = this.getReadableDatabase();
String[] params=new String[]{id};
String selectQuery = "SELECT Content FROM " + TABLE_ITEMS +" WHERE "+ITEM_ID+"=?";
Cursor c=db.rawQuery(selectQuery,params);
c.moveToFirst();
int index= c.getCount();
int indexd= c.getColumnIndex(ITEM_CONTENT);
System.out.print("Count query"+indexd);
return c.getString(index);
}
答案 0 :(得分:2)
使用它:
return c.getString(indexd);
这是你真正想要获得的价值。你在那里使用index
,它返回光标中的记录数。
更好的做法是:
String getItemDetailsWp(String id){
System.out.print(id);
SQLiteDatabase db = this.getReadableDatabase();
String[] params=new String[]{id};
String selectQuery = "SELECT Content FROM " + TABLE_ITEMS +" WHERE "+ITEM_ID+"=?";
Cursor c=db.rawQuery(selectQuery,params);
if(c.getCount()>0){
c.moveToFirst();
int index= c.getCount();
int indexd= c.getColumnIndex(ITEM_CONTENT);
System.out.print("Count query"+index);// use index instead of indexd to print total records in query
return c.getString(index);// return value of column number specified in indexd
}
else
return "";// when no records found
}
答案 1 :(得分:0)
这是正确的代码
int index= c.getCount(); // this will return total rows found
int indexd= c.getColumnIndex(ITEM_CONTENT); // this is the column index by giving the column name.
System.out.print("Count query"+indexd);
return c.getString(indexd); // here you need to pass the column index but you passing the index which was total number of rows
答案 2 :(得分:0)
Cursor c=db.rawQuery(selectQuery,params);
返回大小为0的光标,更改代码以检查光标是否有项目,然后通过以下方式移动到第一个位置:
Cursor c=db.rawQuery(selectQuery,params);
if(c.getCount()>0)
{
c.moveToFirst();
int index= c.getCount();
int indexd= c.getColumnIndex(ITEM_CONTENT);
System.out.print("Count query"+indexd);
return c.getString(index);
}
return "";
答案 3 :(得分:0)
听起来你正试图从空的结果集中读取。
答案 4 :(得分:0)
检查你的数据库,查询返回一个大小为0的游标,所以你试图在索引0处访问游标,因此错误。 重新思考查询并检查数据库中的值。
答案 5 :(得分:0)
您可能正在访问0行光标。改为:
// moveToFirst itself will return false if there is no entry on Cursor
if(c.moveToFirst()){
int cursorCount = c.getCount();
int indexd = c.getColumnIndex(ITEM_CONTENT);
System.out.print("Count query"+index);
// You should getString(ColumnIndex) not CursorCount
return c.getString(indexd);
} else
return "";
答案 6 :(得分:0)
当您传递记录数而不是列号时,您将获得索引超出范围的异常。 作为最佳编码实践,检查光标是否有记录,即它是空的还是包含记录。 使用此
String getItemDetailsWp(String id){
System.out.print(id);
SQLiteDatabase db = this.getReadableDatabase();
String[] params=new String[]{id};
String selectQuery = "SELECT Content FROM " + TABLE_ITEMS +" WHERE "+ITEM_ID+"=?";
Cursor c=db.rawQuery(selectQuery,params);
if(c.getCount()>0){
c.moveToFirst();
int index= c.getCount();
int indexd= c.getColumnIndex(ITEM_CONTENT);
System.out.print("Count query"+index);
return c.getString(indexd);
}
else
return "";// when no records found
}