我正在尝试在双向链表中使用自定义数据类型。我能够创建列表,但是当我尝试调用insert函数时,它会出错。是什么导致了这个错误?
main.cpp中:
#include "command.h" //my custom class
#include "doublyLinkedList.h"
int main(){
//create a queue of jobs:
doublyLinkedList<command>* queue = new doublyLinkedList<command>;
//creating a new command:
command *c = new command();
c->createCommand();
c->print();
const command *d = new command(c->name, c->description, c->shellString);
queue->insert(*d); //problem line
};
doublyLinkedList.h的插入函数:
template <class Type>
void doublyLinkedList<Type>::insert(const Type& insertItem)
{
nodeType<Type> *current; //pointer to traverse the list
nodeType<Type> *trailCurrent; //pointer just before current
nodeType<Type> *newNode; //pointer to create a node
bool found;
newNode = new nodeType<Type>; //create the node
newNode->info = insertItem; //store the new item in the node
newNode->next = NULL;
newNode->back = NULL;
if(first == NULL) //if the list is empty, newNode is
//the only node
{
first = newNode;
last = newNode;
count++;
}
else
{
found = false;
current = first;
while (current != NULL && !found) //search the list
if (current->info >= insertItem)
found = true;
else
{
trailCurrent = current;
current = current->next;
}
if (current == first) //insert newNode before first
{
first->back = newNode;
newNode->next = first;
first = newNode;
count++;
}
else
{
//insert newNode between trailCurrent and current
if (current != NULL)
{
trailCurrent->next = newNode;
newNode->back = trailCurrent;
newNode->next = current;
current->back = newNode;
}
else
{
trailCurrent->next = newNode;
newNode->back = trailCurrent;
last = newNode;
}
count++;
}//end else
}//end else
}//end insert
代码适用于整数和字符串,但不适用于“命令”类型。
错误:
In file included from main.cpp:2:0:
doublyLinkedList.h: In member function âvoid doublyLinkedList<Type>::insert(const Type&) [with Type = command]â:
main.cpp:34:18: instantiated from here
doublyLinkedList.h:171:13: error: no match for âoperator>=â in âcurrent->nodeType<command>::info >= insertItemâ
doublyLinkedList.h:171:13: note: candidates are:
/usr/include/c++/4.6/bits/stl_pair.h:232:5: note: template<class _T1, class _T2> bool std::operator>=(const std::pair<_T1, _T2>&, const std::pair<_T1, _T2>&)
/usr/include/c++/4.6/bits/stl_iterator.h:315:5: note: template<class _Iterator> bool std::operator>=(const std::reverse_iterator<_Iterator>&, const std::reverse_iterator<_Iterator>&)
/usr/include/c++/4.6/bits/stl_iterator.h:365:5: note: template<class _IteratorL, class _IteratorR> bool std::operator>=(const std::reverse_iterator<_IteratorL>&, const std::reverse_iterator<_IteratorR>&)
/usr/include/c++/4.6/bits/basic_string.h:2621:5: note: template<class _CharT, class _Traits, class _Alloc> bool std::operator>=(const std::basic_string<_CharT, _Traits, _Alloc>&, const std::basic_string<_CharT, _Traits, _Alloc>&)
/usr/include/c++/4.6/bits/basic_string.h:2633:5: note: template<class _CharT, class _Traits, class _Alloc> bool std::operator>=(const std::basic_string<_CharT, _Traits, _Alloc>&, const _CharT*)
/usr/include/c++/4.6/bits/basic_string.h:2645:5: note: template<class _CharT, class _Traits, class _Alloc> bool std::operator>=(const _CharT*, const std::basic_string<_CharT, _Traits, _Alloc>&)
答案 0 :(得分:3)
您似乎正在尝试对列表进行排序,但是您没有为command
定义比较运算符。如果您想按原样使用它,则需要为您的类型实现operator>=
。
它的签名可能看起来像这样:
bool operator>= (const command& a, const command& b);