Haskell Cardguess游戏

时间:2012-10-02 09:37:45

标签: haskell

我正在写一个Cardguess游戏,用户设置答案并让PC猜测。对于我的项目,输入卡号为2.

然后,我需要编写cardguess算法。 我创建了卡模块。

data Suit = Club | Diamond | Heart | Spade
      deriving (Eq, Ord, Bounded, Enum)

suitchars = "CDHS"

data Rank =
    R2 | R3 | R4 | R5 | R6 | R7 | R8 | R9 | R10 |
    Jack | Queen | King | Ace
         deriving (Eq, Ord, Bounded, Enum)

rankchars = "23456789TJQKA"

data Card = Card {suit::Suit, rank::Rank}
      deriving (Eq, Bounded)

instance Ord Card where
    compare (Card s1 r1) (Card s2 r2) =
        let suitorder = compare s1 s2
            in  if suitorder == EQ then compare r1 r2 else suitorder

instance Enum Card where
    fromEnum (Card s r) = (fromEnum s)*13 + (fromEnum r)
    toEnum n = (Card s r)
     where s = toEnum (n `div` 13)
           r = toEnum (n `mod` 13)

我的策略是将Suit和Rank分成两部分。最初的猜测可能是Card Club R5Card Heart Jack

然后我将得到反馈,并且根据它,我会尝试nextGuess,所以到目前为止,直到得到正确的答案。

我写了initialGuess函数。

我把剩余的卡片放在GameState

initialGuess :: Int -> ([Card], GameState)
initialGuess card_number 
     | card_number == 2   = ((Card Club R5):(Card Heart J),cardDeck)

现在,我需要编写nextGuess代码。

nextGuess :: ([Card],GameState) -> (Int,Int,Int,Int,Int) ->([Card],GameState)

(Int,Int,Int,Int,Int)是反馈值。 我如何表示第一个参数([Card],GameState),这意味着之前的猜测卡和之前的GameState

2 个答案:

答案 0 :(得分:1)

由于我不理解你的问题,而且你是初学者,我会在你的帖子的其他一些方面挑剔。

  1. 你有

    initialGuess card_number 
         | card_number == 2   = ((Card Club R5):(Card Heart J),cardDeck)
    

    接受您现在只需要initialGuess 2工作,您的列表语法错误。你的意思是

    initialGuess card_number 
         | card_number == 2   = (Card Club R5 : Card Heart J : [], cardDeck)
    

    initialGuess card_number 
         | card_number == 2   = ([Card Club R5, Card Heart J], cardDeck)
    

    他们的意思相同,但后者更清楚。

  2. 你有

    instance Ord Card where
        compare (Card s1 r1) (Card s2 r2) =
            let suitorder = compare s1 s2
                in  if suitorder == EQ then compare r1 r2 else suitorder
    

    如果您import Data.Monoid,您可以更简单地将其写为

    instance Ord Card where
        compare (Card s1 r1) (Card s2 r2) = compare s1 s2 `mappend` compare r1 r2
    

    但更好的方法是将其遗漏并要求编译器为您编写代码:

    data Card = Card {suit::Suit, rank::Rank}
          deriving (Eq, Ord, Bounded)
    

    生成的Ord实例根据您的需要使用词典排序。

答案 1 :(得分:1)

这里很难读懂你的想法,但也许你想要这样的东西:

startGuessing guesses state = do
  feedBack <- readFeedback
  let (newGuess, newState) = nextGuess (guesses, state) feedback
  startGuessing (guesses ++ newGuess) newState

main = do
  let (guesses, state) = initialGuess 2      
  startGuessing guesses state