我有这样的查询:
SELECT DATE,REGION,COUNT(*)
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION,DATE DESC
结果是 什么是正确的查询,如下面的捕获
有人能帮助我吗?
答案 0 :(得分:4)
此类查询称为PIVOT
。不幸的是,MySQL没有PIVOT
函数,因此您需要使用CASE
语句和聚合函数来复制函数。
如果您知道要转换的列数,则可以对值进行硬编码:
select region,
SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
from ALL_ID_DATA
group by region;
select region,
COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
from ALL_ID_DATA
group by region;
然后将其添加到现有查询中,它将是:
SELECT REGION,
SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION
OR
SELECT REGION,
COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION
现在,如果您有未知数量的日期转换为列,那么您可以使用prepared statements,您的查询将与此类似(请参阅SQL Fiddle with Demo):
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(case when date = ''',
date,
''' then 1 else 0 end) AS ''',
Date(date), ''''
)
) INTO @sql
FROM ALL_ID_DATA;
select @sql;
SET @sql = CONCAT('SELECT region, ', @sql, '
FROM ALL_ID_DATA
GROUP BY region');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
然后将原始查询放在预准备语句中,最终查询将是:
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(case when date = ''',
date,
''' then 1 else 0 end) AS ''',
Date(date), ''''
)
) INTO @sql
FROM ALL_ID_DATA;
select @sql;
SET @sql = CONCAT('SELECT region, ', @sql, '
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION=''inbound''
AND REASON_1 = ''complaint''');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
答案 1 :(得分:1)