Question

我有这样的查询：

SELECT DATE,REGION,COUNT(*)
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION,DATE DESC

结果是 capture 什么是正确的查询，如下面的捕获

result 有人能帮助我吗？

Answer 1

此类查询称为PIVOT。不幸的是，MySQL没有PIVOT函数，因此您需要使用CASE语句和聚合函数来复制函数。

如果您知道要转换的列数，则可以对值进行硬编码：

select region,
  SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
  SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
  SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
from ALL_ID_DATA
group by region;

select region,
  COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
  COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
  COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
from ALL_ID_DATA
group by region;

见SQL Fiddle with Demo。

然后将其添加到现有查询中，它将是：

SELECT REGION,
  SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
  SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
  SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
  AND DIRECTION='inbound'
  AND REASON_1 = 'complaint'
GROUP BY REGION

OR

SELECT REGION,
  COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
  COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
  COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
  AND DIRECTION='inbound'
  AND REASON_1 = 'complaint'
GROUP BY REGION

现在，如果您有未知数量的日期转换为列，那么您可以使用prepared statements，您的查询将与此类似（请参阅SQL Fiddle with Demo）：

SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'sum(case when date = ''',
      date,
      ''' then 1 else 0 end) AS ''',
      Date(date), ''''
    )
  ) INTO @sql
FROM ALL_ID_DATA;

select @sql;

SET @sql = CONCAT('SELECT region, ', @sql, ' 
                   FROM ALL_ID_DATA
                   GROUP BY region');

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

然后将原始查询放在预准备语句中，最终查询将是：

SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'sum(case when date = ''',
      date,
      ''' then 1 else 0 end) AS ''',
      Date(date), ''''
    )
  ) INTO @sql
FROM ALL_ID_DATA;

select @sql;

SET @sql = CONCAT('SELECT region, ', @sql, ' 
                   FROM ALL_ID_DATA
                   WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
                   AND DIRECTION=''inbound''
                   AND REASON_1 = ''complaint''');

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

Answer 2

我认为你正在寻找这个： http://www.artfulsoftware.com/infotree/queries.php#78

如何在excel中显示mysql中的数据，如pivot

2 个答案: