Question

可能重复：
UIPopovercontroller dealloc reached while popover is still visible

我正在创建一个通用应用程序并尝试从相机胶卷中选择一个图像。在iPhone上运行良好，iPad需要弹出，所以已经完成了，现在不断出现错误

-[UIPopoverController dealloc] reached while popover is still visible.

我研究过：

Stack Link

和谷歌，没有解决这个问题

现在，任何建议都表示赞赏

我已经在.h

中实现了popover委托

的.m

 - (void)logoButtonPressed:(id)sender /////////////iPad requires seperate method ////////////////
 {                                        

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {

LogCmd();
UIImagePickerController *imagePicker = [[UIImagePickerController alloc] init];
imagePicker.sourceType = UIImagePickerControllerSourceTypePhotoLibrary;
imagePicker.delegate = self;
imagePicker.allowsEditing = YES;
////////
imagePicker.modalPresentationStyle = UIModalPresentationCurrentContext;
////////
[self presentModalViewController:imagePicker animated:YES];


}

else

{

    // We are using an iPad
    UIImagePickerController *imagePickerController = [[UIImagePickerController alloc] init];
    imagePickerController.delegate = self;
    UIPopoverController *popoverController=[[UIPopoverController alloc] initWithContentViewController:imagePickerController];
    popoverController.delegate=self;


    [popoverController presentPopoverFromRect:((UIButton *)sender).bounds inView:sender permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];


   }


  }

我现在也试过这个：

·H

 @property (strong) UIPopoverController *pop;

的.m

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {            ///code added

LogCmd();
UIImagePickerController *imagePicker = [[UIImagePickerController alloc] init];
imagePicker.sourceType = UIImagePickerControllerSourceTypePhotoLibrary;
imagePicker.delegate = self;
imagePicker.allowsEditing = YES;
[self presentModalViewController:imagePicker animated:YES];


    ///code added////////////////////////////

}

else {

    if (self.pop) {
        [self.pop dismissPopoverAnimated:YES];
    }
    // If usingiPad
    UIImagePickerController *imagePickerController = [[UIImagePickerController alloc] init];

    UIPopoverController *popoverController=[[UIPopoverController alloc] initWithContentViewController:imagePickerController];


    [popoverController presentPopoverFromRect:((UIButton *)sender).bounds inView:sender permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];

Answer 1

您实例化弹出窗口并将其分配给本地变量：

UIPopoverController *popoverController=[[UIPopoverController alloc] initWithContentViewController:imagePickerController];

一旦方法返回，变量就会超出范围，并且对象被释放，因为它不再拥有所有者。

您应该做的是声明一个strong属性来分配弹出窗口。您已使用pop属性完成此操作。因此，现在您需要做的就是在分配弹出窗口时将其分配给您的属性。这使您成为对象的所有者，因此不会取消分配。

self.pop = [[UIPopoverController alloc] initWithContentViewController:imagePickerController];
[self.pop presentPopoverFromRect:((UIButton *)sender).bounds inView:sender permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];

希望这有帮助！

弹出错误 - 弹出时仍然可以看到[UIPopoverController dealloc]

1 个答案: