我正在使用Rails 2.3,我有3个表,用于管理建筑物的用户权限。 mygroups表是用户和建筑物所属的组列表。 mygroupsbuildings是具有相关组的建筑物列表。 mygroupsusers是具有关联组的用户列表。
create_table "mygroups", :force => true do |t|
t.string "name"
t.integer "user_id"
t.string "user_name"
t.integer "permissions"
end
create_table "mygroupbuildings", :force => true do |t|
t.integer "mygroup_id"
t.integer "building_id"
end
create_table "mygroupusers", :force => true do |t|
t.integer "mygroup_id"
t.integer "user_id"
t.string "user_name"
end
我想创建一个查询,查明特定的user_id是否是与特定building_id相同的组的成员。
我已设置以下关联:
class Mygroup < ActiveRecord::Base
has_many :mygroupusers
has_many :mygroupbuildings
end
class Mygroubuilding < ActiveRecord::Base
belongs_to :mygroup
has_many :mygroupusers, :through => :mygroup
end
class Mygroupuser < ActiveRecord::Base
belongs_to :mygroup
has_many :mygroupbuildings, :through => :mygroup
end
我写了以下查询:
Mygroupuser.find(:all,
:include => :mygroupbuildings,
:select => "mygroupbuildings.building_id, mygroupusers.user_id",
:conditions => ["mygroupbuildings.building_id = '#{building.id}' AND mygroupusers.user_id = '#{current_user.user_id}'"])
这给我以下错误:
ActiveRecord :: StatementInvalid(Mysql ::错误:'on子句'中的未知列'mygroups.mygroup_id':SELECT mygroupusers
。id
AS t0_r0,mygroupusers
。{{1 AS t0_r1,mygroup_id
。mygroupusers
AS t0_r2,user_id
。mygroupusers
AS t0_r3,user_name
。mygroupusers
AS t0_r4,{{1 } {。{1}} AS t0_r5,created_at
。mygroupusers
AS t1_r0,updated_at
。mygroupbuildings
AS t1_r1,id
。mygroupbuildings
AS t1_r2,mygroup_id
。mygroupbuildings
AS t1_r3,coursewalk_id
。mygroupbuildings
AS t1_r4 FROM created_at
LEFT OUTER JOIN mygroupbuildings
ON({{1} }。updated_at
= mygroupusers
。mygroups
)LEFT OUTER JOIN mygroupusers
ON(id
。mygroups
= mygroup_id
。{{ 1}})WHERE(mygroupbuildings.building_id ='2'和mygroupusers.user_id = '55')):
谢谢,
尼克,
答案 0 :(得分:0)
这是查询需要如何设置以返回包含查询的user_id和building_id的组:
Mygroup.find(:all,
:include => [:mygroupbuildings, :mygroupusers],
:conditions => ["mygroupbuildings.building_id = #{building.id} AND mygroupusers.user_id = #{current_user.user_id}"])