CustomClass{
int ID;
int numberToSum;
float numToAverage;
}
IEnumerable<CustomClass> results = MethodToPopulateIEnumerable();
List<int> listOfIDs = MethodToGetListOfIDs();
我希望如何处理这些内容,请点击我的IEnumberable<CustomClass>
,然后选择List<int> listOfIDs
中ID的所有内容,然后我希望将numberToSum
的值加起来并将其保存在变量中并获取numToAverage
属性的平均值并将其保存在变量中。
最优雅的方法是什么?
答案 0 :(得分:7)
我认为你正在寻找这样的东西:
IEnumerable<CustomClass> results = MethodToPopulateIEnumerable();
List<int> listOfIDs = MethodToGetListOfIDs();
查询语法
var query = from c in results
where listOfIds.Any(x => x == c.ID)
select c;
方法语法
var query = results.Where(c => listOfIds.Any(x => x == c.ID));
<强>计算强>
int numberToSum = query.Sum(x => x.numberToSum);
float numToAverage = query.Average(x => x.numToAverage);
另一种方法可以解决其他成员关注的一些性能问题,但仍允许查询为友好的(linq-to-entities
,linq-to-sql
):
var calculations = (from c in results
where listOfIds.Any(x => x == c.ID)
group c by 1 into g
select new {
numberToSum = g.Sum(x => x.numberToSum ),
numToAverage = g.Average(x => x.numToAverage),
}).FirstOrDefault();
答案 1 :(得分:1)
我认为是这样的:
var matchingIdsList = results.Where(x => listsOfIDs.Any(y => y == x.Id));
var sum = matchingIdsList.Sum(x=> x.numberToSum);
var average = matchingIdsList.Average(x=> x.numToAverage);
答案 2 :(得分:0)
我会按照以下方式执行此操作 - 不是很优雅但效率更高:
// Load IDs into a hashset so Contains is O(1) not O(n)
var hashSetOfIDs = new HashSet<int>(listOfIDs);
// Aggreagate count and both sums in one pass, then calculate average.
var result = results.Where(cc => hashSetOfIDs.Contains(cc.ID)).Aggregate(
new { Count = 0, Sum = 0, AverageSum = 0f },
(a, cc) => new {
Count = a.Count + 1,
Sum = a.Sum + cc.numberToSum,
AverageSum = a.AverageSum + cc.numToAverage },
a => new {
Sum = a.Sum,
Average = a.Count > 0 ? a.AverageSum / a.Count : float.NaN });
// Extract results
var sum = result.Sum;
var average = result.Average;
答案 3 :(得分:0)
var results = MethodToPopulateIEnumerable();
var listOfIDs = MethodToGetListOfIDs();
int numberToSum = 0;
float numberToAverage = 0;
var selected = results.Where(c => listOfIDs.Contains(c.ID)).Select(c =>
{
numberToSum += c.numberToSum;
numberToAverage += c.numToAverage;
return c;
}).ToList();
float average = numberToAverage/selected.Count;