我正在尝试根据已输入数据库的用户值添加“已检查的语句”。
我将数据库端设计为q1,q2等,并且只有一个带有“a”,“b”或“c”的varchar。
我基本上希望代码检索答案并将其放入复选框中作为“已检查”,由于某种原因我无法让它工作。
到目前为止,我的代码是:<?php
//retreive questions from database and put into question box
$query2 = "SELECT `QuestionId`, `Question`, `Opt1`, `Opt2`, `Opt3`, `Opt4`,`Answer` FROM `pf_questions`";
$question2 = mysql_query($query2);
while($row = mysql_fetch_array($question2)){
$id = $row['QuestionId'];
$question = $row['Question'];
$opt1 = $row['Opt1'];
$opt2 = $row['Opt2'];
$opt3 = $row['Opt3'];
$opt4 = $row['Opt4'];
$answer = $row["Answer"];
?>
<div id="ContainerQuestion">
<span class="Question">Question <?php echo $id; ?>. <?php echo $question; ?></span>
<p><input type=radio name='q<?php echo $id; ?>' value="a"> <?php echo $opt1; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' value="b"> <?php echo $opt2; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' value="c"> <?php echo $opt3; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' value="d"> <?php echo $opt4; ?> </p>
</div>
<?php
}
?>
我可以在while函数中进行查询,只需让每个输入类型说if($ row ['1'] ='a')echo“checked ='checked'”;或者我错了吗?
任何帮助都会很棒。 感谢
答案 0 :(得分:1)
<p><input type=radio name='q<?php echo $id; ?>' <?php echo $answer == 'a'?'checked="checked"':'' ?> value="a"> <?php echo $opt1; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' <?php echo $answer == 'b'?'checked="checked"':'' ? value="b"> <?php echo $opt2; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' <?php echo $answer == 'c'?'checked="checked"':'' ? value="c"> <?php echo $opt3; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' <?php echo $answer == 'd'?'checked="checked"':'' ? value="d"> <?php echo $opt4; ?> </p>
答案 1 :(得分:0)
将单选按钮更改为:
<p><input type=radio name='q<?php echo $id; ?>' value="a" <?php echo ($row[1] == 'a') ? 'selected="selected"':''; ?>> <?php echo $opt1; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' value="b" <?php echo ($row[1] == 'b') ? 'selected="selected"':''; ?>> <?php echo $opt2; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' value="c" <?php echo ($row[1] == 'c') ? 'selected="selected"':''; ?>> <?php echo $opt3; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' value="d" <?php echo ($row[1] == 'd') ? 'selected="selected"':''; ?>> <?php echo $opt4; ?> </p>
答案 2 :(得分:0)
以这种方式试试
<p><input type="radio" name="q<?php echo $id; ?>" value="a" <?php if($opt1=='a') echo "checked='checked'"; ?>><?php echo $opt1; ?> </p>
答案 3 :(得分:0)
您只需使用
检查答案是否与选项匹配即可<?=( $answer == 'a')?("checked='checked'"):(""); ?>
如果答案与echo checked='checked'
选项相同,则为空字符串
完整代码
<?php
//retreive questions from database and put into question box
$query2 = "SELECT `QuestionId`, `Question`, `Opt1`, `Opt2`, `Opt3`, `Opt4`,`Answer` FROM `pf_questions`";
$question2 = mysql_query($query2);
while($row = mysql_fetch_array($question2)){
$id = $row['QuestionId'];
$question = $row['Question'];
$opt1 = $row['Opt1'];
$opt2 = $row['Opt2'];
$opt3 = $row['Opt3'];
$opt4 = $row['Opt4'];
$answer = $row["Answer"];
?>
<div id="ContainerQuestion">
<span class="Question">Question <?php echo $id; ?>. <?php echo $question; ?></span>
<p><input type=radio name='q<?php echo $id; ?>' <?=( $answer == 'a')?("checked='checked'"):(""); ?> value="a"> <?php echo $opt1; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' <?=( $answer == 'b')?("checked='checked'"):(""); ?> value="b"> <?php echo $opt2; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' <?=( $answer == 'c')?("checked='checked'"):(""); ?> value="c"> <?php echo $opt3; ?> </p>
<p><input type=radio name='q<?php echo $id; ?>' <?=( $answer == 'd')?("checked='checked'"):(""); ?> value="d"> <?php echo $opt4; ?> </p>
</div>
<?php
}
?>
注意假设您的答案存储在$row["Answer"];
中与选项(a,b,c,d)相同
答案 4 :(得分:0)
假设$answer
字段是'a','b','c'或'd',这应该有效:
<p><input type=radio name='q<?php echo $id; ?>' value="a" <?php if($answer == 'a'){ echo "checked='checked'";} ?>> <?php echo $opt1; ?> </p>