Question

我想在一个过程中使用Date_add 2次，但是它返回0行（虽然它应该返回行）

这是程序

 select av.*, ap.*,c.* from tbl_available av 
 left join tbl_appointment ap on av.avHours = ap.appointmenttime 
 and ap.calendarid = kalenderId 
 and ap.appointmentdate = DATE_ADD(dag, INTERVAL 6 DAY)
 left join tbl_client c on ap.clientid = c.clientid
 where av.avCalendarId = KalenderId 
 and av.avDays = DayOfweek(DATE_ADD(dag, INTERVAL 6 DAY)) 
 order by avHours;

没有date_add

提前感谢！

//修改

我现在拥有的：

select av.*, ap.*,c.*, ab.absentid from tbl_available av 
left join tbl_appointment ap on av.avHours = ap.appointmenttime 
and ap.calendarid = kalenderId 
and ap.appointmentdate BETWEEN dag AND DATE_ADD(dag, INTERVAL 6 DAY)
and (av.avDays = DayOfweek(ap.appointmentdate) OR ap.appointmentdate IS NULL)
left join tbl_client c on ap.clientid = c.clientid
left join tbl_absent ab on av.avHours = ab.ababsent
and ab.abHoliday = dag
and ab.abCalendarID = kalenderId
where av.avCalendarId = kalenderId 
order by avDays,avHours;

但ab.absentid没有被提取，为什么呢？：（

Answer 1

我不确定完全你想要什么，但在整个星期，尝试类似的事情：

select av.*, ap.*,c.* from tbl_available av 
left join tbl_appointment ap on av.avHours = ap.appointmenttime 
and ap.calendarid = kalenderId 
and ap.appointmentdate BETWEEN dag AND DATE_ADD(dag, INTERVAL 6 DAY)
and (av.avDays = DayOfweek(ap.appointmentdate) OR ap.appointmentdate IS NULL)
left join tbl_client c on ap.clientid = c.clientid
where av.avCalendarId = KalenderId 
order by avHours;

我正在使用BETWEEN指定ap.appointmentdate的日期范围。 av.avDays更改为与ap.appointmentdate相关联，或者也显示没有约会的行（假设此行为，因为LEFT JOIN上有tbl_appointment）。我已经离开了DayOfweek(dag) ...，因为你看了整整一周所以这是多余的。

mysql date_add在程序中2次

1 个答案: