Question

我有一个SQL查询，看起来像这样：

select name, count (*) from Results group by name order by name

和另一个相同的，从归档结果表中加载，但字段是相同的。

select name, count (*) from Archive_Results group by name order by name

如何在一个查询中将两者结合起来？（因此，群组仍将正常运作）。我尝试使用union all，但是它不起作用。我错过了什么？

Answer 1

select tem.name, count(*) 
from(select name from results
union all
select name from archive_results) as tem
group by name
order by name

Answer 2

如果您有支持索引和相对较高的计数，这样的事情可能比建议的解决方案快得多：

SELECT name, MAX(Rcount) + MAX(Acount) as TotalCount
FROM (
  SELECT name, count(*) as Rcount, 0 as Acount
  FROM Results GROUP BY name
  UNION ALL
  SELECT name, 0, count(*)
  FROM Archive_Results
  GROUP BY name
) AS Both
GROUP BY name
ORDER BY name;

Answer 3

你的目标是......

计算“鲍勃的所有实例” 琼斯“在两个表格中（例如）
计算“鲍勃的所有实例” 琼斯“在Results中排成一排所有“鲍勃琼斯”的实例 Archive_Results在另一行？

假设它是＃1你想要的东西......

SELECT name, COUNT(*) FROM
(SELECT name FROM Results UNION ALL SELECT name FROM Archive_Results)
GROUP BY name
ORDER BY name

Answer 4

select T1.name, count (*)
from (select name from Results 
      union 
      select name from Archive_Results) as T1
group by T1.name order by T1.name

在SQL查询中一起使用union和count（*）

4 个答案: