正确使用计数功能

时间：2012-10-01 00:27:08

标签： sql sql-server sql-server-2008 tsql

在Enrollment_Changes表中，列出的电话型号是订户在该日期更改的电话。

如果Enrollment_Changes没有后续更改，则订阅者更改为TO的电话将列在P_Enrollment表中

例如，订户12345678在2011年1月5日注册了RAZR。 2011年11月1日，他改变了RAZR。您可以通过2012年5月19日的Enrollment_Changes上的下一笔交易查看他更改为TO的内容。

您如何找到首次使用iPhone 3注册的子计数？

以下是我创建表格的代码

创建表格：TBL 1 

USE [Test2]
GO

/****** Object:  Table [dbo].[P_ENROLLMENT]    ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

CREATE TABLE [dbo].[P_ENROLLMENT](
    [Subid ] [float] NULL,
    [Enrollment_Date] [datetime] NULL,
    [Channel] [nvarchar](255) NULL,
    [Region] [nvarchar](255) NULL,
    [Active_Status] [float] NULL,
    [Drop_Date] [datetime] NULL,
    [Phone_Model] [nvarchar](255) NULL
) ON [PRIMARY]

GO

TBL 2 

USE [Test2]
GO

/****** Object:  Table [dbo].[ENROLLMENT_CHANGES]     ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

CREATE TABLE [dbo].[ENROLLMENT_CHANGES](
    [Subid] [float] NULL,
    [Cdate] [datetime] NULL,
    [Phone_Model] [nvarchar](255) NULL
) ON [PRIMARY]

GO

插入TBL1 

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12345678, '2011-01-05 00:00:00', 'Retail', 'Southeast', 1, NULL, 'iPhone 4');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12346178, '2011-03-13 00:00:00', 'Indirect Dealers', 'West', 1, NULL, 'HTC Hero');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12346679, '2011-05-19 00:00:00', 'Indirect Dealers', 'Southeast', 0, '2012-03-15 00:00:00', 'Droid 2');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12347190, '2011-07-25 00:00:00', 'Retail', 'Northeast', 0, '2012-05-21 00:00:00', 'iPhone 4');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12347701, '2011-08-14 00:00:00', 'Indirect Dealers', 'West', 1, NULL, 'HTC Hero');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12348212, '2011-09-30 00:00:00', 'Retail', 'West', 1, NULL, 'Droid 2');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12348723, '2011-10-20 00:00:00', 'Retail', 'Southeast', 1, NULL, 'Southeast');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12349234, '2012-01-06 00:00:00', 'Indirect Dealers', 'West', 0, '2012-02-14 00:00:00', 'West');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12349745, '2012-01-26 00:00:00', 'Retail', 'Northeast', 0, '2012-04-15 00:00:00', 'HTC Hero');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12350256, '2012-02-11 00:00:00', 'Retail', 'Southeast', 1, NULL, 'iPhone 4');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12350767, '2012-03-02 00:00:00', 'Indirect Dealers', 'West', 1, NULL, 'Sidekick');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12351278, '2012-04-18 00:00:00', 'Retail', 'Midwest', 1, NULL, 'iPhone 3');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12351789, '2012-05-08 00:00:00', 'Indirect Dealers', 'West', 0, '2012-07-04 00:00:00', 'iPhone 3');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12352300, '2012-06-24 00:00:00', 'Retail', 'Midwest', 1, NULL, 'Droid 2');

INSERT INTO [P_ENROLLMENT]([Subid ], [Enrollment_Date], [Channel], [Region], [Active_Status], [Drop_Date], [Phone_Model]) 
    VALUES(12352811, '2012-06-25 00:00:00', 'Retail', 'Southeast', 1, NULL, 'Sidekick');

插入TBL2 

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12345678, '2011-11-01 00:00:00', 'RAZR');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12346178, '2012-01-07 00:00:00', 'HTC Hero');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12348723, '2012-01-28 00:00:00', 'RAZR');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12350256, '2012-02-21 00:00:00', 'Blackberry Bold');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12349745, '2012-05-05 00:00:00', 'HTC Hero');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12345678, '2012-05-19 00:00:00', 'Palm Pre');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12347190, '2012-05-20 00:00:00', 'HTC Hero');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12350256, '2012-05-21 00:00:00', 'Blackberry Bold');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12349234, '2012-06-04 00:00:00', 'Palm Pre');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12346178, '2012-06-05 00:00:00', 'iPhone 3');

INSERT INTO [ENROLLMENT_CHANGES]([Subid], [Cdate], [Phone_Model]) 
    VALUES(12350767, '2012-06-10 00:00:00', 'iPhone 3');

3 个答案:

答案 0 :(得分：4)

计数

select COUNT(*) Total
from
(
    select e.*,
        rn = row_number() over (partition by e.subid order by c.cdate desc),
        first_model = coalesce(c.phone_model, e.phone_model)
    from [P_ENROLLMENT] e
    left join [ENROLLMENT_CHANGES] c on c.subid = e.subid
) x
where rn=1 and first_model = 'iPhone 3'

<小时/> 对于所有记录

select *
from
(
    select e.*,
        rn = row_number() over (partition by e.subid order by c.cdate desc),
        first_model = coalesce(c.phone_model, e.phone_model)
    from [P_ENROLLMENT] e
    left join [ENROLLMENT_CHANGES] c on c.subid = e.subid
) x
where rn=1 and first_model = 'iPhone 3'
order by subid

答案 1 :(得分：1)

你想知道表格中的第一条记录是否是iPhone 3.这样的事情：

select count(*)
from (select e.*,
             row_number() over (partition by subid order by enrollment_date) as seqnum
      from p_enrollment e
     ) e
where seqnum = 1 and phone_model = 'iPhone 3'

答案 2 :(得分：1)

也许我的想法太简单了，但是以下任何一种都不会做你想要的事情吗？：

SELECT      Phone_Model
            , COUNT(*) AS Initially_Enrolled
FROM        p_enrollment
GROUP BY    Phone_Model

（使用SQLFiddle：http://sqlfiddle.com/#!3/68258/4）

或

SELECT      COUNT(*) AS Initially_Enrolled
FROM        p_enrollment
WHERE       Phone_Model = 'iPhone 3'

（使用SQLFiddle：http://sqlfiddle.com/#!3/68258/3）

由于您只想要初始注册，因此ENROLLMENT_CHANGES表无关紧要。

相关问题
最新问题