选择查询中的Android错误

时间:2012-09-30 07:06:05

标签: android android-sqlite

以下是导致问题的数据库方法:

 public Cursor fetchRecord(String pin,String category)throws SQLException
{

Cursor c=mDb.query(DATABASE_TABLE, new String[]
{KEY_ROWID,KEY_NAME,KEY_PHONE,KEY_CATEGORY,KEY_PINCODE},
KEY_PINCODE + "= ?" + "AND" + KEY_CATEGORY + "= ?",
new String[]{pin,category}, null, null, KEY_NAME);

    if (c!= null) {
        c.moveToFirst();
    }
    return c;
}

每当我提供输入并在第一个活动中单击“执行”按钮时,它就会关闭 日志猫说:

Caused by: android.database.sqlite.SQLiteException: near "ANDcategory": syntax error: , while compiling: SELECT _id, name, phone, category, pincode FROM details WHERE pincode= ?ANDcategory= ? ORDER BY name

2 个答案:

答案 0 :(得分:1)

密码和密码之间必须有空格。类别,在你的where子句中。

简单地替换

"AND"

" AND "


public Cursor fetchRecord(String pin,String category)throws SQLException 
{ 

        Cursor c=mDb.query(DATABASE_TABLE, new String[]
 {KEY_ROWID,KEY_NAME,KEY_PHONE,KEY_CATEGORY,KEY_PINCODE},
KEY_PINCODE + "= ?" + 
" AND " + KEY_CATEGORY + "= ?",new String[]{pin,category}, null, null, KEY_NAME); 

    if (c!= null) { 
        c.moveToFirst(); 
    } 
    return c; 
}

答案 1 :(得分:0)

阅读异常,它告诉你需要知道的一切:

syntax error: , while compiling: SELECT _id, name, phone, category, pincode FROM details WHERE pincode= ?ANDcategory= ? ORDER BY name