Question

我有一个显示用户活动的JSF表。

<p:lineChart id="logins" value="#{StatisticsController.weekActivity}" legendPosition="e"  
                                 title="Weekly Logins" seriesColors="4D94FF, 1975FF, 005CE6, 0047B2" minY="0" maxY="200"/>


public class Statistics implements Serializable {

    private CartesianChartModel weeksActivity;

    public Statistics() {  
        createweeksActivity(); 

    }  

    public CartesianChartModel getweekActivity() {  
        return weeksActivity;  
    }

    private void createweeksActivity() {  
        weeksActivity = new CartesianChartModel();  

        ChartSeries boys = new ChartSeries();  
        boys.setLabel("Active Accounts");  

        boys.set("Monday", 120);  
        boys.set("Tuesday", 100);  
        boys.set("Wednesday", 44);  
        boys.set("Thursday", 150);  
        boys.set("Friday", 120);
        boys.set("Saturday", 82);  
        boys.set("Sunday", 115);  

        ChartSeries girls = new ChartSeries();  
        girls.setLabel("Blocked Accounts");  

        girls.set("Monday", 52);  
        girls.set("Tuesday", 60);  
        girls.set("Wednesday", 110);  
        girls.set("Thursday", 135);  
        girls.set("Friday", 120);
        girls.set("Saturday", 140);  
        girls.set("Saturday", 130);  
        girls.set("Sunday", 140);  

        weeksActivity.addSeries(boys);  
        weeksActivity.addSeries(girls);  
    }  


}

我想按时顺序显示当前日期。例如：现在我收到了这个订单：Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday 如果今天是星期三，我想在打开网页时收到此订单：

Thursday, Friday, Saturday, Sunday, Monday, Tuesday, Wednesday

我如何解决这个问题？

EDIT:

我用这种方式更新了代码：

private void createweeksActivity()
    {

        weeksActivity = new CartesianChartModel();

        ChartSeries activeAccounts = new ChartSeries();
        activeAccounts.setLabel("Active Accounts");

        ChartSeries blockedAccounts = new ChartSeries();
        blockedAccounts.setLabel("Blocked Accounts");

        GregorianCalendar calendar = new GregorianCalendar();
        DateFormat df = new SimpleDateFormat("EEEE");
        for (int i = 0; i < 7; i++)
        {
            calendar.add(Calendar.DATE, 1);
            System.out.println(df.format(calendar.getTime()));
            activeAccounts.set(df.format(calendar.getTime()), getNumberOfLogins(df.format(calendar.getTime())));
            blockedAccounts.set(df.format(calendar.getTime()), getNumberOfLogins(df.format(calendar.getTime())));
        }       

        weeksActivity.addSeries(activeAccounts);
        weeksActivity.addSeries(blockedAccounts);
    }

    public int getNumberOfLogins(String day){

        // Get here the number of logins using SQL command
        // Example: SELECT * FROM HISTORY WHERE DAY = day;

        return 100;
    }

我想它会起作用。

Answer 1

GregorianCalendar calendar = new GregorianCalendar();
DateFormat df = new SimpleDateFormat("EEEE");
for (int i = 0; i < 7; i++) {
    calendar.add(Calendar.DATE, 1);
    System.out.println(df.format(calendar.getTime()));
}

GregorianCalendar表示我们的格里高利历下的瞬间。它的无参数构造函数将其初始化为当前时间。

DateFormat用于格式化日期。您可以使用(Gregorian)Calendar方法将getTime()转换为日期。 “EEEE”是指一周中最长的一天。

(Gregorian)Calendar.add()方法允许向日历的任何字段（年，月，日，小时等）添加值。由于你想要迭代一周中的几天，我从明天开始，每次迭代都加1天。

the javadoc中提供了所有内容。

Answer 2

根据日历，将你的星期几周作为地图的星期几。

然后使用Calendar获取当前日期并使用Modular Arithmetic来更改排序。

类似的东西：

//This you can do it one time and then use it in your program
Map<Integer, String> daysOfWeek = new HashMap<Integer,String>();
daysOfWeek.put(Calendar.MONDAY, "Monday");
daysOfWeek.put(Calendar.TUESDAY, "Tuesday");
//so on and so forth.



//Now the code that will be running 
//You get your current Day  (Which will be the last one you want to see)
int weekday = calendar.get(Calendar.DAY_OF_WEEK);

//Start with next value (modulus 7 since you don't want overflow)
int currDay = (weekday+1) % 7;


//Go over the seven Days
for(int i = 0; i < 7; i++) {
    String currDay = daysOfWeek.get(currDay);  //Get your Day String

    //Here do whatever you need to do to set up the DAY in JSF

    currDay = (currDay+1) % 7;  //Moving currDay to the next Day
 }

如何始终显示一周的最后一天

2 个答案: