我有一个CakePHP应用程序,允许用户与其他用户成为朋友。这是通过用户名表上的HABTM关系通过友情表进行的。
friends表有:id,user_id,friend_id和状态字段。
关系模型如下:
public $hasAndBelongsToMany = array(
'User'=>array(
'className' => 'User',
'joinTable' => 'friends',
'with' => 'Friend',
'foreignKey' => 'user_id',
'associationForeignKey' => 'friend_id'
)
);
因此,例如,如果我想列出登录用户的朋友,我有以下内容:
$user = $this->User->find('first', array('conditions' => array('User.id' => $this->Auth->user('id'))));
$friends = $this->User->find('first',
array(
'conditions'=>array(
'User.id'=>$user['User']['id']
),
'contain'=>array(
'User'=>array(
'conditions'=>array(
'Friend.status'=>1
)
)
)
)
);
$this->set('friends', $friends);
现在我遇到的问题是在尝试显示此列表时,获取好友信息!
如果我对$ friends进行调试,我会得到:
array(
'User' => array(
'password' => '*****',
'id' => '6',
'username' => 'test',
'email' => 'test@test.com',
'firstname' => 'Test',
'lastname' => 'User',
(int) 0 => array(
'password' => '*****',
'id' => '8',
'username' => 'johndoe',
'email' => 'john@doe.com',
'firstname' => 'John',
'lastname' => 'Doe',
'Friend' => array(
'id' => '1',
'user_id' => '6',
'friend_id' => '8',
'created' => '0000-00-00 00:00:00',
'status' => '1'
)
)
)
)
如何显示朋友列表呢?正如我所做的那样:
<?php foreach ($friends as $friend) : ?>
<li><?php echo $this->Html->link($friend['User']['firstname']. ' '. $friend['User']['lastname'], array('controller'=>'users','action'=>'view','userName'=>$friend['User']['username'])); ?></li>
<?php endforeach; ?>
但我得到:Undefined index: User [APP/View/Friends/index.ctp, line 44]
任何想法是什么我做错了?我假设它与视图中没有正确使用的数组有关。
答案 0 :(得分:0)
我认为你应该尝试一下:
$friends = $this->User->find('first', array(
'conditions' => array('User.id' => $this->Auth->user('id')),
'contain' => array('Friend' => array(
'conditions' => array('Friend.status' => 1)
))
));
你会:
array(
'User' => array(
'password' => '',
'id' => '',
'username' => '',
'Friend' => array(
0 => array(),
1 => array(),
2 => array()
)
)
)
在您看来:
<?php foreach ($friends['User']['Friend'] as $friend): ?>
<li><?php echo $this->Html->link($friend['User']['firstname']. ' '. $friend['User']['lastname'], array('controller'=>'users','action'=>'view','userName'=>$friend['User']['username'])); ?></li>
<?php endforeach; ?>
希望这有帮助。
修改强>
使用Containable:
$this->User->Behaviors->load('Containable');
$this->User->contain('Friend' => array(
'conditions' => array('Friend.status' => 1),
'User'
));
$user = $this->User->read(null, $this->Auth->user('id'));
$this->User->Behaviors->unload('Containable');