我在MATLAB中编写了一个函数,但它不会返回我的输出。它返回第一个输出为ans = a#但是就是这样。我认为function[argout1,argout2,...argoutn=funcname(in1,in2,...inn)
会以argout1= a #
,argout2= a #
等格式返回所有输出。
我意识到我可以使用disp()
或其他一些内置函数,但是当你有一个函数文件时,有什么意义呢。该功能正在访问excel电子表格中的输入,但我认为这不应该有所作为。任何帮助将不胜感激。
代码如下。
function[y_int1, y_int2, Youngs_Modulus, Poissons_Ratio, Youngs_Modulus_Percent_diff, Poissons_Ratio_Percent_diff, RMS1, RMS2]= Lab3_EC(elong1,elong2,elat1,elat2,thick,width,load,N)
%average longitudinal strain
avgLongs=((elong1)+(elong2))/2;
%average lateral strain
avgLats=((elat1)+(elat2))/2;
%Find's the area of the sample
A=thick*width;
%Finds the applied stress
stress=load./A;
%declares a variable x1 for Long Strain
x1=avgLongs;
%declares a variable y1 for Applied Stress
y1=stress;
%Declares variables to compute slope1
x1bar=mean(x1);
y1bar=mean(y1);
sxy1=sum(x1.*y1);
sx1=sum(x1);
sy1=sum(y1);
sx1s=sum(x1.*x1);
sx11s=(sum(x1))^2;
slope1=(N*sxy1-sx1*sy1)/(N*sx1s-sx11s);
y_int1=y1bar-slope1*x1bar;
%x points
xp=linspace(min(x1),max(x1));
% y points
yp1=slope1*xp+y_int1;
%Declares variables to compute slope 2
%Since our second calculation of linear regression uses Average
%Longitudinal Stress we can re-use the variable x1
y2=abs(avgLats);
y2bar=mean(y2);
sxy2=sum(x1.*y2);
sy2=sum(y2);
slope2=(N*sxy2-sx1*sy2)/(N*sx1s-sx11s);
y_int2=y2bar-slope2*x1bar;
%y points
yp2=slope2*xp+y_int2;
%preallocate space for error1 vector
Error1=zeros(N,1);
%compute error1
for i=1:N;
Error1(i)= (stress(i)-y_int1-slope1*avgLongs(i))^2;
end
Error1=sum(Error1(5));
%preallocate space for error2 vector
Error2=zeros(N,1);
for i=1:N;
Error2(i)=(abs(avgLats(i))-y_int2-slope2*avgLongs(i))^2;
end
Error2=sum(Error2(5));
RMS1=sqrt(Error1/N);
RMS2=sqrt(Error2/N);
Lab_2_E=(stress(5)-stress(1))/(avgLongs(5)-avgLongs(1));
Lab_2_v=(abs(avgLats(5)-avgLats(1))/(avgLongs(5)-avgLongs(1)));
Youngs_Modulus=slope1;
Poissons_Ratio=slope2;
Youngs_Modulus_Percent_diff=((abs(Youngs_Modulus-Lab_2_E))/Lab_2_E)*100;
Poissons_Ratio_Percent_diff=((abs(Poissons_Ratio-Lab_2_v))/Lab_2_v)*100;
%Plot stress strain diagram and poisson's ratio
figure(1), plot(avgLongs,stress,'k',x1,y1,'o',xp,yp1,':g'),hold on,...
xlabel('Long Strain(in/in)'),ylabel('Stress(psi)'),...
title('Stress vs. Long Strain'), legend('Exp','data points','Calc',...
'Location','SouthEast')
figure(2),plot(avgLongs,abs(avgLats),x1,y2,'+',xp,yp2,'-- m'),hold on,...
xlabel('Long Strain(in/in)'),ylabel('Lat Strain(in/in)'),...
title('Poisson''s Ratio'),legend('Exp','data points','Calc',...
'Location','SouthEast')
答案 0 :(得分:2)
假设你有一个函数fun
:
[o1, o2, o3, o4, o5] = fun(i1, i2, i3, i4);
如果你执行
fun(in1, in2, in3)
只有一个输出参数:ans
默认输出参数。这将获得函数头中定义的第一个输出参数的值(即o1
)。
如果您想要更多输出,则必须指定它们:
[out1, out2, out3] = fun(in1, in2, in3);
现在out1
,out2
和out3
将分别包含功能中指定给o1
,o2
和o3
的值。< / p>
您一定要仔细阅读function documentation。