Question

我正在编写一个简单的Linux C程序，以帮助我更好地理解IPC，现在我正在尝试用管道构建它。
我有一个代码库，我运行两个不同的终端窗口作为两个不同的可执行文件（因此它们可以相互通信）。但是我没有做正确的事情，因为我从来没有得到任何数据可读，但我不确定是什么......

注意这不是完整的代码，我切断了输出/输入/验证以节省空间。但是在下面的计划的评论中已经注意到了。

void main()
{
  int pipefd[2], n;
  char input = 0;
  char buffer[100] = {0};
  char outpipe[100] = {0};

  if(pipe(pipefd) < 0) {
    printf("FAILED TO MAKE PIPES\n");
    return;
  }

  printf("Starting up, read fd = %d, write fd = %d\n", pipefd[0],pipefd[1]);

  do {
    //print menu options (send message, get message, get my fd, 
    // set a fd to talk to, quit)

    // if "send a message":
    {
      printf("What would you like to send?\n");
      fgets(buffer, 100, stdin);
      write(pipefd[1], buffer, strlen(buffer));
    }
    //else if "read a message":
    {
      if(open(outpipe, 0) < 0)
          printf("Couldn't open the pipe!\n");
      else {
        n = read(outpipe, buffer, 100);
        printf("I got a read of %d bytes\nIt was %s\n",n, buffer);
        close(outpipe);
      }
    }
    //else if "get my file descriptor":
      printf("My fd tag is: /proc/%d/fd/%d\n", (int)getpid(), pipefd[0]);
    //else if "set a file descriptor to talk to":
    {
      printf("What is the pipe's file descriptor?\n");
      fgets(outpipe, 100, stdin);
      n = strlen(outpipe) - 1;
      outpipe[n] = '\0';
    }
  } while (input != 'Q');
return;
}

我知道管道已成功创建，我验证了文件描述符已到位：

lr-x------ 1 mike users 64 Sep 26 23:31 3 -> pipe:[33443]
l-wx------ 1 mike users 64 Sep 26 23:31 4 -> pipe:[33443]

看起来权限是正常的（在管道3上读取，在管道4上写入）。

我这样使用它：

//terminal 1
Pick an option:
3
My fd tag is: /proc/8956/fd/3

//terminal 2
Pick an option:
4
What is the pipe's file descriptor?
/proc/8956/fd/3

Pick an option:
1
What would you like to send?
hello

//terminal 1
Pick an option:
2
I got a read of -1 bytes
It was

我在这里做的事情有什么明显的错吗？我的读取总是得到“-1”的返回值......

Answer 1

您似乎误解了管道是如何工作的。管道是匿名文件描述符，不是文件系统中的文件。 /proc/<pid>/fd中您无需关心的文件。

以下是对您要做的事情的重写：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>

int main(void)
{
    int pipefds[2];
    char input[128];
    char output[128];
    ssize_t nread;

    if (pipe(pipefds) == -1)
    {
        perror("Could not create pipe");
        return EXIT_FAILURE;
    }

    printf("Enter input: ");
    if (fgets(input, sizeof(input), stdin) == NULL)
    {
        perror("Could not read input");
        return EXIT_FAILURE;
    }

    /* "Remove" newline from input */
    if (input[strlen(input) - 1] == '\n')
        input[strlen(input) - 1] = '\0';

    /* Now write the received input to the pipe */
    if (write(pipefds[1], input, strlen(input) + 1) == -1)
    {
        perror("Could not write to pipe");
        return EXIT_FAILURE;
    }

    /* Now read from the pipe */
    if ((nread = read(pipefds[0], output, sizeof(output))) == -1)
    {
        perror("Could not reaf from pipe");
        return EXIT_FAILURE;
    }

    /* We don't need to terminate as we send with the '\0' */

    printf("Received: \"%s\"\n", output);

    return EXIT_SUCCESS;
}

Answer 2

这是您最关心的问题：

./ipctest.c: In function ‘main’:

./ipctest.c:32:9: warning: passing argument 1 of ‘read’ makes integer from pointer without a cast [enabled by default]
/usr/include/unistd.h:361:16: note: expected ‘int’ but argument is of type ‘char *’

./ipctest.c:34:9: warning: passing argument 1 of ‘close’ makes integer from pointer without a cast [enabled by default]
/usr/include/unistd.h:354:12: note: expected ‘int’ but argument is of type ‘char *’

查看某个函数所需的数据类型......：）

简单的Linux管道程序，没有收到数据

2 个答案: