Question

任何人都可以帮我创建mongo查询以删除＆＃34; name＆＃34; ：＆＃34; gdfgdfgdfg＆＃34;嵌入式文件

对象存储在Mongo db。

中

{
    "_id": ObjectId("50656f33a4e82d3f98291eff"),
    "description": "gdfgdfgdfg",
    "menus": [
    {
        "name": "gdfgdfgdfg"**,
        "description": "dfgdgd",
        "text": "dfgdfg",
        "key": "2",
        "onSelect": "yyy",
        "_id": ObjectId("50656f3ca4e82d3f98291f00")
    },
    {
        "name": "dfg",
        "description": "dfgdfgdfgdf",
        "text": "dfgdgf",
        "key": "1",
        "onSelect": "uuuu",
        "_id": ObjectId("50656f44a4e82d3f98291f01")
    }
    ]
}

任何人都帮助我，我是Mongo的新手

Answer 1

在JavaScript shell中，您可以这样做：

var query = {"_id": ObjectId("50656f33a4e82d3f98291eff")};
db.collection.update(query, {'$pull':{ menus: {name : 'gdfgdfgdfg'} } });

或使用Id。

db.collection.update(query, {'$pull': { menus: {"_id": ObjectId("50656f3ca4e82d3f98291f00")} } });

使用Java Driver应该是这样的：

BasicDBObject query = new BasicDBObject("_id", new ObjectId("50656f33a4e82d3f98291eff"));

BasicDBObject docToRemove = new BasicDBObject("name", "gdfgdfgdfg");

BasicDBObject updateCommand = new BasicDBObject("$pull", new BasicDBObject("menus", docToRemove));

collection.update(query, updateCommand);

Answer 2

Mongo不会让您删除嵌入的文档。您需要做的是从集合中获取对象，删除列表中的一个对象，然后将其保存回数据库。

obj = db.collection.findOne({"_id": ObjectId("50656f33a4e82d3f98291eff")});
menus = obj.menus.splice(0,1); // Or some other way to manually delete
                               // the one item in the list
db.collection.update({"_id": ObjectId("50656f33a4e82d3f98291eff")},
                     {$set: {menus: menus}});

这很复杂，请参阅here。

编辑：如果您不知道索引，可以试试这个：

obj = db.collection.findOne({"_id": ObjectId("50656f33a4e82d3f98291eff")});
var i = 0;
for(i=0;i<obj.menus.length;i++) {
    if(obj.menus[i].name === "gdfgdfgdfg")
        break;
}
menus = obj.menus.splice(i,1);
db.collection.update({"_id": ObjectId("50656f33a4e82d3f98291eff")},
                     {$set: {menus: menus}});

Answer 3

$conditionArray=array("_id"=>ObjectId("50656f33a4e82d3f98291eff"));
$dataArray=array("description"=>"");
$db->$collectionName->update($conditionArray,array('$unset' =>$dataArray))->limit(1);

如何在Mongo中为嵌入对象创建查询？

3 个答案: