Question

可能重复：
Dynamically bind mysqli_stmt parameters and then bind result (PHP)

任何人都可以帮助我如何在PHP上创建动态bind_result。我的查询字段不知道自动态创建以来有多少字段（例如，根据日期范围创建年份字段）。下面是我的脚本，并突出显示问题在哪里。

public function getMarketingReports($datefrom,$dateto)
    {
        $yearfrom = date("Y", strtotime($datefrom));
        $yearto = date("Y", strtotime($dateto));

        //create year fields
        $concatYear = "";
        for($year=$yearfrom;$year<=$yearto;$year++){
            $concatYear .= "SUM(IF(c.datecreated='".$year."',IF(LOWER(c.fullTimeEployeeType)='basic hour rate', c.fullTimeEployeeTypeAmount*2080 , c.fullTimeEployeeTypeAmount),0)) ".$year.",";
        }


        $reportdata = array();
        $db = Connection::Open();
        $stmt = $db->stmt_init();
        if($stmt->prepare("SELECT p.Code `PositionCode`,
                                  p.name `PositionName`,
                                  l.value `Location`,
                                  ".$concatYear."
                                  SUM(b.field205) `TotalEmployees`
                             FROM c1 c
                            INNER JOIN b1 b
                               ON c.registrationid=b.id
                            INNER JOIN positions p
                               ON c.positionid=p.id
                            INNER JOIN lookupvalues l
                               ON c.location=l.id
                            WHERE c.`status`!=2
                              AND c.datecreated BETWEEN ? AND ?
                            GROUP BY c.positionid,c.location,YEAR(c.datecreated)")){

            $datefrom = $datefrom." 00:00:00";
            $dateto = $dateto." 23:59:59";
            $stmt->bind_param("ss",$datefrom,$dateto);
            $stmt->execute();
            $stmt->bind_result
            (
                $positionCode,
                $positionName,
                $location,

                **//getting bind result data here for year fields**

                $totalEmployees
            );
            while($stmt->fetch())
            {
                $surveydata = array();
                $surveydata['positionCode'] = $positionCode;
                $surveydata['positionName'] = $positionName;
                $surveydata['location'] = $location;

                **//storing of data here for year fields**

                $surveydata['totalEmployees'] = $totalEmployees;
                array_push($reportdata,$surveydata);
            }
        }
        Connection::Close();
        return $reportdata;

    }

有可能吗？任何人都可以帮我解决这个问题

Answer 1

首先，生成年字段的代码有一个很好的语法错误：

"SUM(IF(c.datecreated='".$year."',IF(LOWER(c.fullTimeEployeeType)='basic hour rate', c.fullTimeEployeeTypeAmount*2080 , c.fullTimeEployeeTypeAmount),0) ".$year.","

SUM(开场语句缺少右括号。最重要的是，你有一个浮动".$year."，它不是任何封闭方法的一部分（但是，它可以用作别名;我不习惯在没有前面{{1}的情况下看到它虽然 - 所以这可能是我的错误）。为了猜测，我会说用AS替换".$year."并且应该修复该部分：

如果$concatYear .= "SUM(IF(c.datecreated='".$year."',IF(LOWER(c.fullTimeEployeeType)='basic hour rate', c.fullTimeEployeeTypeAmount*2080 , c.fullTimeEployeeTypeAmount),0)),";添加实际上是别名，则可以在其前面添加右括号以关闭$year函数。

关于动态绑定变量，我理想的解决方案实际上来自a similar question/answer SO（这是直接复制/粘贴，我不相信它，但我喜欢它= P）：

SUM()

Answer 2

您必须call_user_func_array：

call_user_func_array(array($stmt, "bind_result"), $argArray);

以这种方式填写$argArray：

$years = array();

$concatYear = "";
for($year=$yearfrom;$year<=$yearto;$year++){
    $concatYear .= "SUM(IF(c.datecreated='".$year."',IF(LOWER(c.fullTimeEployeeType)='basic hour rate', c.fullTimeEployeeTypeAmount*2080 , c.fullTimeEployeeTypeAmount),0) ".$year.",";

    // track the years you need
    $years[] = $year;

}

...

//you prepare all the vars here
$argArray = array(
    $positionCode,
    $positionName,
    $location
);

//loop the years
foreach($years as $y)
{

    $argArray[] = ${$y};

}

$argArray[] = $annualSalary;
$argArray[] = $totalEmployees;
$argArray[] = $yearOfData;

多年以后你用这种方式做事：

...

foreach($years as $y)
{

$surveydata[$y] = ${$y};

}

PHP上的动态bind_result

2 个答案: