Question

为什么data_dummy哈希中的值会增加？我想用它来启动零值的另一个哈希值！

fau[f.label][:hash] = data_dummy #  ==>{"name 1" => 0, "name 2" => 0} but in the second loop it contains data from the first loop e.g. {"name 1" => 2, "name 2" => 0}

当使用字符串而不是变量dummy_data时，代码按预期工作。

fau[f.label][:hash] = {"name 1" => 0, "name 2" => 0}

我不能这样做因为'名字X'正在改变......

这对我来说很奇怪！

完整代码

fau = {}
series = []
labels = [{:value => 0, :text => ''}]

data_dummy = {}
source.each do |c|
  data_dummy[c.name] = 0
end
i = 0
data_dummy.each do |k,v|
  i += 1
  labels.push({:value => i, :text => k})
end

source.each do |s|
  logger.debug "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~"
  logger.debug "Source: '#{s.name}'|'#{fault_labels[s.fault_id.to_s].label}' => #{s.cnt}"
  con_name = s.name #TODO: Cut name (remove location like left,right, ...)
  f = fault_labels[s.fault_id.to_s]
  unless fau.has_key?(f.label)
    # init faults-hash 'fau'
    fau[f.label] = {:total => 0, :hash => {}, :color => f.color, :name => f.label} #, :data => []
    # add all connector_names as keys with value = 0
    logger.debug "init :hash with #{data_dummy}" #  ==>{"name 1" => 0, "name 2" => 0} but in the second loop it contains data from the first loop e.g. {"name 1" => 2, "name 2" => 0}
    fau[f.label][:hash] = data_dummy
    # this way the number of incidents are all in the same order for each fault (first dimension key)
    # and all get at least a value of 0
 end
  logger.debug "Count up fau['#{f.label}'][:total] = #{fau[f.label][:total]} + #{s.cnt} (where connector '#{s.name}' and fault '#{f.label}')"
  logger.debug "Count up fau['#{f.label}'][:hash]['#{con_name}'] = #{fau[f.label][:hash][con_name]} + #{s.cnt}"
  fau[f.label][:total] += s.cnt
  fau[f.label][:hash][con_name] += s.cnt
  logger.debug "result :hash with #{fau[f.label][:hash].inspect}}"
end

Answer 1

因为Ruby散列与所有Ruby对象一样，都是引用和复制，例如hash2 = hash1只创建引用的副本。修改hash2将修改hash1，实际上，它们只是同一事物的不同别名。

您想要使用克隆方法。

hash2 = hash1.clone

另见How do I copy a hash in Ruby?

请注意，即使这只创建一个浅表副本，如果您有嵌套哈希（例如myhash = {"key1" => "value1", "key2" => {"key2a" => "value2a"}}），则必须进行深层复制。根据上述问题的Wayne Conrad's answer，这样做的方法是：

def deep_copy(o)
  Marshal.load(Marshal.dump(o))
end

Answer 2

如果要复制哈希值，则需要使用dup方法：

foo = {"name 1" => 0, "name 2" => 0}
bar = foo
foo["name 2"] += 1
foo
=> {"name 2"=>1, "name 1"=>0}
bar
=> {"name 2"=>1, "name 1"=>0}

baz = foo.dup
foo["name 2"] += 1
foo
=> {"name 2"=>2, "name 1"=>0}
baz
=> {"name 2"=>1, "name 1"=>0}

Ruby似乎引用了一个变量，而不是应对它的价值

2 个答案: