Question

我有一个字符向量，我想从中排除第二个向量中存在的元素。我仍然不知道在这种情况下如何处理否定，同时还要考虑整个向量

vector[vector ! %in% vector2]

我显然可以vector[vector != single_character]，但这只适用于单个角色。

Answer 1

你很亲密

vector[!vector %in% vector2]

或者，即使你说“不使用setdiff”

setdiff(vector, vector2)

Answer 2

vector1 <- letters[1:4]
set.seed(001)
vector2 <- sample(letters[1:15], 10, replace=TRUE)

 vector1
[1] "a" "b" "c" "d"
vector2
 [1] "d" "f" "i" "n" "d" "n" "o" "j" "j" "a"

vector2 [!(vector2 %in% vector1)] # elements in vector2 that are not in vector1
[1] "f" "i" "n" "n" "o" "j" "j"

Answer 3

您可以定义新的运算符

 `%ni%` = Negate(`%in%`)

Answer 4

现在提供了更优雅的解决方案：

library(textclean)
# master character vector
vector1 = c("blue", "green", "red")
# vector containing elements to be removed from master vector
vector2 = c("green", "red")
drop_element_fixed(vector1, vector2)

# Output:
# [1] "blue"

从另一个向量中排除向量的元素，而不是使用setdiff

4 个答案: