Question

对标题感到抱歉。这可能有点令人困惑！我正在使用的样本表如下：

     ID         Quantity         Type
 -----------------------------------------------
     1             14             PO
     1              2             PO  
     1              4             MH  
     1              3             MH
     1              2             MH
     2             16             PO
     2             12             MH
     2              9             MH

这就是我想要做的。我想将所有数量的ID = 1和Type = PO（14 + 2）加总为SUM_IN。然后，我想将所有数量的ID = 1和Type = MH（4 + 3 + 2）加总为SUM_OUT。完成此操作后，我想比较两个并返回值，只有SUM_OUT＆gt; SUM_IN。因此，对于ID = 1，将不会返回ID = 2的情况，因为（12 + 9）＆gt; 16。

有没有办法在SQL中执行此操作，或者我是否需要使用PL / SQL和变量来完成任务。我对PL / SQL的经验很少，但从逻辑上讲，变量似乎是解决问题的最简单方法。我知道select语句可以存储在变量中，但我不知道如何。这是我的两个SQL选择

  SELECT SUM(QUANTITY) AS SUM_IN
  FROM TRANSLOG
  WHERE TYPE IN ('PO')
  AND ID = '1'

  SELECT SUM(QUANTITY) AS SUM_OUT
  FROM TRANSLOG
  WHERE TYPE IN ('MH')
  AND ID = '1'

因此，如果我可以将这两个设置为变量，那么任务不应该太难，对吧???

提前感谢您的帮助。

Answer 1

select ID, 
    sum ( Quantity * case Type when 'po' then 1 else 0 end ) as SUM_IN,
    sum ( Quantity * case Type when 'mh' then 1 else 0 end ) as SUM_OUT
from translog
group by ID
having sum ( Quantity * case Type when 'po' then 1 else -1 end ) < 0

Answer 2

SELECT CASE WHEN b.SUM_OUT > a.SUM_IN then b.SUM_OUT else '' END as SUM_OUT,
       CASE WHEN b.SUM_OUT > a.SUM_IN then a.SUM_IN else '' END as SUM_IN
FROM

(SELECT ID,SUM(QUANTITY) AS SUM_IN
FROM TRANSLOG
WHERE TYPE IN ('PO')
AND ID = '1'
GROUP BY ID,Type
) a

INNER JOIN 

(SELECT ID,SUM(QUANTITY) AS SUM_OUT
FROM TRANSLOG
WHERE TYPE IN ('MH')
AND ID = '1'
GROUP BY ID,Type
) b

ON a.ID=b.ID

Answer 3

正如您使用plsql标记标记了问题我假设您要执行查询的RDBMS是Oracle。如果是这样，那么这是另一种方法（使用DECODE函数）获得你想要的结果集。

select *
  from (select id
             , sum(Quantity*decode(tp, 'PO', 1, 0)) as sum_in
             , sum(Quantity*decode(tp, 'MH', 1, 0)) as sum_out
         from t1
        group by id
        order by id  )
 where sum_out > sum_in

结果：

ID    SUM_IN    SUM_OUT
-----------------------
 2     16        21

如果您希望显示其余列以及sum_in，sum_out，则以下查询可能会派上用场：

select id
     , quantity
     , Tp
     , sum_in
     , sum_out
  from (select id
             , quantity
             , tp
             , sum(Quantity*decode(tp, 'PO', 1, 0)) over(partition by id) as sum_in
             , sum(Quantity*decode(tp, 'MH', 1, 0)) over(partition by id) as sum_out
         from t1
       )
 where sum_out > sum_in

结果：

Id    Quantity    Tp    Sum_In    Sum_Out 
---------------------------------------------
2      16         PO     16        21 
2      12         MH     16        21 
2      9          MH     16        21

SQL：对列中的某些项进行求和，并从该列中的另一个数字中减去它

3 个答案: