PHP在后台运行FFMPEG,并找出它何时完成

时间:2012-09-27 02:21:53

标签: php process background ffmpeg

  

可能重复:
  Run a ffmpeg process in the background

我想知道是否有任何简单的方法可以在后台运行和ffmpeg进程,以便人们可以离开页面。如果你这样做,那么告诉ffmpeg进程是否正在运行,当它完成时,将数据库更新为“finished”。如果需要,我会发布我的代码。谢谢! 这是处理页面上的代码:

<?php
$name = $_FILES['upload_file']['name'];
$type = $_FILES['upload_file']['type'];
$size = $_FILES['upload_file']['size'];
$tmpname = $_FILES['upload_file']['tmp_name'];

if (!$title) {
    $title = $name;
}

if (!$description) {
    $description = "No description available.";
}

$string = substr(str_shuffle(str_repeat('ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789',10)),0,10);
$videoname = "$string.mp4";
$date = date("F d, Y"); // October 09, 2010
$srcFile = $tmpname;
mkdir("users/$usercode/uploads/$string");
mkdir("users/$usercode/uploads/$string/HD");
mkdir("users/$usercode/uploads/$string/regular");
mkdir("users/$usercode/uploads/$string/mobile_upload");
mkdir("users/$usercode/uploads/$string/thumbnails");
$destFile1 = "/users/$usercode/uploads/$string/HD/$string.mp4";
$destFile2 = "/users/$usercode/uploads/$string/regular/$string.mp4";
$destFile3 = "/users/$usercode/uploads/$string/mobile_upload/$string.mp4";
$ffmpegPath = "/usr/local/bin/ffmpeg"; 
$flvtool2Path = "/usr/bin/flvtool2";
$yamdiPath = "/usr/bin/yamdi";
$mp4boxPath = "/usr/local/bin/MP4Box";
// Create our FFMPEG-PHP class 
$ffmpegObj = new ffmpeg_movie($srcFile); 
// Save our needed variables 
$srcWidth = $ffmpegObj->getFrameWidth(); 
$srcHeight = $ffmpegObj->getFrameHeight(); 
$srcFPS = $ffmpegObj->getFrameRate(); 
$srcAB = $ffmpegObj->getAudioBitRate();  
$srcAR = $ffmpegObj->getAudioSampleRate(); 
$res = $srcWidth . "x" . $srcHeight; 
// Call our convert using exec() 
$iphone1 = getcwd().$destFile1;
$iphone2 = getcwd().$destFile2;
$iphone3 = getcwd().$destFile3;
$low = "854x480";
$local_img = "/users/$usercode/uploads/$string/thumbnails/$string.jpg";
$img = getcwd().$local_img;
$img = preg_replace('/ /','\ ',$img); 
$thumb = "$string.jpg"; 
$cmd = "$ffmpegPath -i $tmpname 2>&1";  
if (preg_match('/Duration: ((\d+):(\d+):(\d+))/s', `$cmd`, $time)) {  
    $total = ($time[2] * 3600) + ($time[3] * 60) + $time[4];  
    $interval = rand(0, $total);  
}  

$img = shell_exec("$ffmpegPath -ss $interval -i $tmpname 2>&1 -s 120x90 -f mjpeg -vframes 1 $img");


if ($srcWidth >= 1280 && $srcHeight >= 720) {
    $out1 = shell_exec("$ffmpegPath -i $tmpname -f mp4 -vcodec libx264 -vpre normal -ab $srcAB -ar $srcAR -b 5000k -r $srcFPS -s $res -acodec libfaac $iphone1");
    $out2 = shell_exec("$mp4boxPath -inter 0.5 $iphone1");
    $out3 = shell_exec("$ffmpegPath -i $tmpname -f mp4 -vcodec libx264 -vpre normal -ab $srcAB -ar $srcAR -b 2000k -r $srcFPS -s $low -acodec libfaac $iphone2");
    $out4 = shell_exec("$mp4boxPath -inter 0.5 $iphone2");
    $out5 = shell_exec("$ffmpegPath -i $tmpname -f mp4 -vcodec libx264 -vpre slow -ab 64k -ar 44100 -b 500k -r 30 -s $low -acodec libfaac $iphone3");
    $out6 = shell_exec("$mp4boxPath -inter 0.5 $iphone3");
    echo 1;
}
else {
    $out3 = shell_exec("$ffmpegPath -i $tmpname -f mp4 -vcodec libx264 -vpre normal -ab 64k -ar 44100 -b 500k -r 30 -s $low -acodec libfaac $iphone2");
    $out4 = shell_exec("$mp4boxPath -inter 0.5 $iphone2");
    $out5 = shell_exec("$ffmpegPath -i $tmpname -f mp4 -vcodec libx264 -vpre slow -ab 64k -ar 44100 -b 500k -r 30 -s $low -acodec libfaac $iphone3");
    $out6 = shell_exec("$mp4boxPath -inter 0.5 $iphone3");          
    echo 1;
}
function generate_random($number_of_characters)
{
        $characters = array();
        $randomchar = "";
        $x = 0;
        for($i = 48; $i < 123; $i++)
        {
                if(ctype_alnum(chr($i)))
                {
                        $characters[$x] = chr($i);
                        $x++;
                }
        }
        for($i = 0; $i < $number_of_characters; $i++)
        {
                $randomchar .= $characters[rand(0, count($characters) - 1)];
        }
        return $randomchar;
}
?>

1 个答案:

答案 0 :(得分:1)

首先,您的代码非常容易受到SQL注入攻击和shell参数攻击。您需要将所有输入转义为SQL和shell命令!

我认为这是解决这个问题的标准方法:

  1. 将您的ffmpeg“job”写入数据库元组。记下作业号,它将是元组的主键。此时,“状态”需要不是“完整”。
  2. 将所有ffmpeg处理代码移动到辅助PHP脚本。通过帮助器,我只是指另一个脚本。称之为“ffmpeg_job_processor.php”。
  3. 通过调用exec('php ffmpeg_job_processor.php '.escapeshellarg($jobNumber).' > /dev/null &');在后​​台运行该脚本脚本将按ID从数据库加载作业,执行所有处理,完成后将更新数据库“完成”。 / LI>
  4. 基于网络的作业监控页面可以通过ID查找相同的元组,轻松显示作业状态。
  5. 诀窍是在后台执行第二个PHP脚本,这样它就会释放你调用的PHP脚本,继续进行而不会阻塞。您必须将stdout传递给/dev/null(Linux框)并使用背景运算符&

    这里有一些更好的信息:Run a ffmpeg process in the background