计算表中的每个用户名

Question

  

可能重复：
  MYSQL COUNT GROUP BY question

$query = "SELECT * FROM product_id_1";

$result = mysql_query($query);

while( $record = mysql_fetch_array($result) ){

$array[] = $record['username'];

$unique_array = array_unique($array);

}


foreach( $unique_array as $list ){
    echo $list.'<br/>';
}

问候语，

我一直试图弄清楚如何应用array_count_unique（）。原因是我需要找出表中每个用户的计数，即亚当出现的次数和abcd出现的次数。

---

更新

根据你们的建议，这就是我所做的：

$query = 'SELECT username, COUNT(*) AS username_count FROM product_id_1 GROUP BY username';

$result = mysql_query($query);

while ($record = mysql_fetch_object($result)) {

    echo $record->username;

    echo $record->username_count;
}

Answer 1

这正是我们拥有RDBMS和SQL的原因：

SELECT COUNT(1) AS username_count, username
FROM
    product_id_1
GROUP BY
    username