Question

假设我有模特

class Widget < ActiveRecord::Base
    has_many :widget_spots

和

class WidgetSpot < ActiveRecord::Base
  belongs_to :widget

另外，在我的MySQL表'widget_spots'中，我有一个列'widget_id'

+--------------------+------------+------+-----+---------+-------+
| Field              | Type       | Null | Key | Default | Extra |
+--------------------+------------+------+-----+---------+-------+
| id                 | int(11)    | NO   | PRI | NULL    |       |
| widget_id          | int(11)    | NO   | PRI | NULL    |       |
                ................
+--------------------+------------+------+-----+---------+-------+

现在，如果在我的rails控制台中，尝试访问widget_spot_ids会出错。

> widget = widgets.find(:first)
> widget.widget_spot_ids
ActiveRecord::UnknownPrimaryKey: ActiveRecord::UnknownPrimaryKey
    from /Users/xxxxx/.rvm/gems/ruby-1.9.2-p320@rails-3.1.1/gems/activerecord-3.1.1/lib/active_record/reflection.rb:374:in `primary_key'
    from /Users/xxxxx/.rvm/gems/ruby-1.9.2-p320@rails-3.1.1/gems/activerecord-3.1.1/lib/active_record/reflection.rb:228:in `association_primary_key'
    from /Users/xxxxx/.rvm/gems/ruby-1.9.2-p320@rails-3.1.1/gems/activerecord-3.1.1/lib/active_record/associations/collection_association.rb:51:in `ids_reader'
    from /Users/xxxxx/.rvm/gems/ruby-1.9.2-p320@rails-3.1.1/gems/activerecord-3.1.1/lib/active_record/associations/builder/collection_association.rb:62:in `block in define_readers'
    from (irb):12
    from /Users/xxxxx/.rvm/gems/ruby-1.9.2-p320@rails-3.1.1/gems/railties-3.1.1/lib/rails/commands/console.rb:45:in `start'
    from /Users/xxxxx/.rvm/gems/ruby-1.9.2-p320@rails-3.1.1/gems/railties-3.1.1/lib/rails/commands/console.rb:8:in `start'
    from /Users/xxxxx/.rvm/gems/ruby-1.9.2-p320@rails-3.1.1/gems/railties-3.1.1/lib/rails/commands.rb:40:in `<top (required)>'
    from script/rails:6:in `require'
    from script/rails:6:in `<main>'

但是，获取实例会给出一个没有错误的列表：> widget.widget_spots执行预期的SQL查询并给出一个列表。

如何确定生成ActiveRecord::UnknownPrimaryKey错误的位置和方式。它试图在哪个数据库中找到哪个主键？

Answer 1

这可能会发生，因为目标widget_spots表的主键由多个字段组成。

（自动生成？）_ id给出了ActiveRecord :: UnknownPrimaryKey错误

1 个答案: