在PHP中没有得到正确的时差

Question

$time1 = "01:00";
$time2 = "04:55";
list($hours1, $minutes1) = explode(':', $time1);
$startTimestamp = mktime($hours1, $minutes1);

list($hours2, $minutes2) = explode(':', $time2);
$endTimestamp = mktime($hours2, $minutes2);

$seconds = $endTimestamp - $startTimestamp;
$minutes = ($seconds / 60) % 60;
$hours = round($seconds / (60 * 60));

echo $hours.':'.$minutes;
exit;

输出4:55，应该是3:55？

这里有什么不对？如果是01:00和02:00，它可以正常工作，但不能与上述相同吗？

Answer 1

使用floor代替round ...

Answer 2

或者只是转换为整数。

$hours = (int) ($seconds / (60 * 60));

Answer 3

PHP可以为您完成太多计算，同时还可以减少出错的可能性

$time1 = Datetime::createFromFormat("h:i", "01:00");
$time2 = Datetime::createFromFormat("h:i", "04:55");

$diff = $time1->diff($time2);
var_dump($diff->format("%h %i"));

输出

string '3:55' (length=4)

Answer 4

使用strtotime：

，您还可以节省一些时间

$time1 = strtotime("01:00");
$time2 = strtotime("04:55");

$seconds = $time2-$time1;
$minutes = ($seconds / 60) % 60;
$hours = floor($seconds / (60 * 60));

echo $hours.':'.$minutes;

如上所述，使用floor将产生您需要的结果：

<强>结果

3:55