Question

需要知道如何在相应字段

中添加缺少空数据的日期

**05/28/2012    NULL
05/29/2012  NULL
05/30/2012  NULL
05/30/2012  Break In
05/30/2012  Break Out
05/31/2012  NULL**

06/03/2012  NULL
06/03/2012  Break In
06/03/2012  Break Out
06/03/2012  In Duty
06/03/2012  Out Duty
06/04/2012  NULL
06/04/2012  In Duty
06/04/2012  Out Duty
06/05/2012  NULL
06/05/2012  Break In
06/05/2012  Break Out
06/06/2012  NULL
06/06/2012  Break In
06/06/2012  Break Out
06/06/2012  In Duty
06/06/2012  Out Duty
06/07/2012  NULL
06/07/2012  In Duty
06/07/2012  Out Duty

06/10/2012  NULL
06/10/2012  Break Out
06/10/2012  In Duty
06/10/2012  Out Duty
06/11/2012  NULL
06/11/2012  In Duty
06/11/2012  Out Duty
06/12/2012  NULL
06/13/2012  NULL
06/14/2012  NULL

我需要的结果是：

05/28/2012  NULL
05/29/2012  NULL
05/30/2012  NULL
05/30/2012  Break In
05/30/2012  Break Out
05/31/2012  NULL
06/01/2012      null
06/02/2012      null
06/03/2012  NULL
06/03/2012  Break In
06/03/2012  Break Out
06/03/2012  In Duty
06/03/2012  Out Duty
06/04/2012  NULL
06/04/2012  In Duty
06/04/2012  Out Duty
06/05/2012  NULL
06/05/2012  Break In
06/05/2012  Break Out
06/06/2012  NULL
06/06/2012  Break In
06/06/2012  Break Out
06/06/2012  In Duty
06/06/2012  Out Duty
06/07/2012  NULL
06/07/2012  In Duty
06/07/2012  Out Duty
06/08/2012      null
06/09/2012      null
06/10/2012  NULL
06/10/2012  Break Out
06/10/2012  In Duty
06/10/2012  Out Duty
06/11/2012  NULL
06/11/2012  In Duty
06/11/2012  Out Duty
06/12/2012  NULL
06/13/2012  NULL
06/14/2012  NULL

Answer 1

最佳选择是保留一个日历表，其中包含您想要计算的若干年的所有日期，然后保持与该表的连接

select date,col1
from calender_table c
left join 
your_table t
on c.[date]=t.[date]

您可以非常轻松地创建日历表。网上有很多脚本。 click for examples

Answer 2

Declare @stDate datetime='05/28/2012'
declare @eddate datetime='06/14/2012'
select DATEADD(day,number,@stdate) from master..spt_values where type='P'
and DATEADD(day,number,@stdate) <= @eddate

此处只需将此结果与日期列上的表格结合即可获取缺少的日期

Answer 3

形成一个带有开始和结束日期范围的日期日历，并与您的表格进行左连接以获得所需的结果。

e.g。

DECLARE @t TABLE(Dt Datetime, Value VARCHAR(20) NULL)
INSERT INTO @t VALUES
('05/28/2012',NULL),
('05/29/2012',NULL),
('05/30/2012',NULL),('05/30/2012','Break In'),('05/30/2012','Break Out'),
('05/31/2012',NULL),
('06/03/2012',NULL),('06/03/2012','Break In'),('06/03/2012','Break Out'),('06/03/2012','In Duty'),('06/03/2012','Out Duty'),
('06/04/2012',NULL),('06/04/2012','In Duty'),('06/04/2012','Out Duty'),
('06/05/2012',NULL),('06/05/2012','Break In'),('06/05/2012','Break Out'),
('06/06/2012',NULL),('06/06/2012','Break In'),('06/06/2012','Break Out'),('06/06/2012','In Duty'),('06/06/2012','Out Duty'),
('06/07/2012',NULL),('06/07/2012','In Duty'),('06/07/2012','Out Duty'),
('06/10/2012',NULL),('06/10/2012','Break Out'),('06/10/2012','In Duty'),('06/10/2012','Out Duty'),
('06/11/2012',NULL),('06/11/2012','In Duty'),('06/11/2012','Out Duty'),
('06/12/2012',NULL),
('06/13/2012',NULL),
('06/14/2012',NULL)


DECLARE @startDate DATETIME, @endDate DATETIME
SELECT @startDate = '2012-05-28', @endDate = '2012-06-14' --yyyy-mm-dd
;WITH Calender AS (
    SELECT @startDate AS CalanderDate
    UNION ALL
    SELECT CalanderDate + 1 FROM Calender
    WHERE CalanderDate + 1 <= @endDate
)
SELECT 
    [Date] = Convert(VARCHAR(10),CalanderDate,101)
    ,Value
FROM Calender c
LEFT JOIN @t t 
ON t.Dt = c.CalanderDate

<强>结果

Date    Value
05/28/2012  NULL
05/29/2012  NULL
05/30/2012  NULL
05/30/2012  Break In
05/30/2012  Break Out
05/31/2012  NULL
06/01/2012  NULL
06/02/2012  NULL
06/03/2012  NULL
06/03/2012  Break In
06/03/2012  Break Out
06/03/2012  In Duty
06/03/2012  Out Duty
06/04/2012  NULL
06/04/2012  In Duty
06/04/2012  Out Duty
06/05/2012  NULL
06/05/2012  Break In
06/05/2012  Break Out
06/06/2012  NULL
06/06/2012  Break In
06/06/2012  Break Out
06/06/2012  In Duty
06/06/2012  Out Duty
06/07/2012  NULL
06/07/2012  In Duty
06/07/2012  Out Duty
06/08/2012  NULL
06/09/2012  NULL
06/10/2012  NULL
06/10/2012  Break Out
06/10/2012  In Duty
06/10/2012  Out Duty
06/11/2012  NULL
06/11/2012  In Duty
06/11/2012  Out Duty
06/12/2012  NULL
06/13/2012  NULL
06/14/2012  NULL

希望这有帮助

查询如何在sql中添加缺少的日期

3 个答案: