奇怪的查询。从另一个表中获取id

时间:2012-09-26 07:46:14

标签: c# mysql

我想要的:我想把作者ID,但我只有作者的名字。来自表格的作者。那么如何在下面的查询中获取作者ID?

INSERT INTO book (title, isbn, author_id) VALUES('" + BookTitle.Text.ToString() + "', '" + BookIsbn.Text.ToString() + "', '(SELECT id FROM author WHERE first_name = '" + BookAuthor.Text.ToString() + "')')";

错误:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Marijn')')' at line 1

我希望我能说明我想要的东西。

谢谢!

3 个答案:

答案 0 :(得分:2)

您不应该将第二个SELECT语句放在单引号中(MySQL将其解释为字符串)。

"INSERT INTO book (title, isbn, author_id) 
VALUES ('" + BookTitle.Text.ToString() + "', '" + BookIsbn.Text.ToString() + "', 
    (SELECT id FROM author WHERE first_name = '" + BookAuthor.Text.ToString() + "'))"

PS请注意,将数据插入数据库的方法使其非常容易受到注入攻击。

答案 1 :(得分:1)

Here you have to have function fn_getID(fname) which will return id.

"INSERT INTO book (title, isbn, author_id) 
VALUES('" + BookTitle.Text.ToString() + "', '" + BookIsbn.Text.ToString() + "'"+fn_getID(BookAuthor.Text.ToString()))

答案 2 :(得分:0)

您当前的查询非常容易受到sql注入攻击。最好的方法是使用SQLCommand and its parameters使用参数化查询。我认为最好在查询中使用INSERT INTO...SELECT

(
"
INSERT INTO book (title, isbn, authorID)
SELECT '" + BookTitle.Text.ToString() + "' as title,
       '" + BookIsbn.Text.ToString() + "' AS isbn,
       id  as authorID
FROM author 
WHERE first_name = '" + BookAuthor.Text.ToString() + "'
"
)

使用ADO.Net

string query =  "INSERT INTO book (title, isbn, authorID)
                SELECT @title as title,
                       @isbn AS isbn,
                       id  as authorID
                FROM author 
                WHERE first_name = @author";

using (MySqlConnection conn = new MySqlConnection("connectionstringHere"))
{
    using (MySqlCommand comm = new MySqlCommand())
    {
        comm.Connection = conn;
        comm.CommandType = CommandType.Text;
        comm.CommandText = query;
        comm.Parameters.AddWithValue("@title", BookTitle.Text.ToString());
        comm.Parameters.AddWithValue("@isbn", BookIsbn.Text.ToString());
        comm.Parameters.AddWithValue("@author", BookAuthor.Text.ToString());
        try
        {
            conn.Open();
            comm.ExecuteNonQuery;
        }
        catch (MySqlException ex)
        {
            // error here
        }
        finally
        {
            conn.Close();
        }
    }
}