平铺排序类：

Question

我正在根据我的纹理图集制作一个自动类型图块系统来绘制我的int [，] tileMap，但是当我运行代码时，我将整个事物侧身并且纹理不会出现，唯一的方法我知道它的侧面是因为绘制纹理的“颜色”与ClearScreen的颜色不同。

平铺排序类：

    public Texture2D Texture { get; set; }
    public int Rows { get; set; }
    public int Columns { get; set; }
    public int totalTiles;
    public int _tileWidth;
    public int _tileHeight;
    public int[] tiles;
    public int[,] tileMap = new int[,] {
            {0,0,0,0,0,0,2,0,0,0,},
            {0,0,0,0,0,2,2,0,0,0,},
            {0,0,0,0,0,2,0,0,0,0,},
            {0,0,0,0,0,2,0,0,0,0,},
            {0,0,0,2,2,2,0,0,0,0,},
            {0,0,0,2,0,0,0,0,0,0,},
            {0,0,0,2,0,0,0,0,0,0,},
            {0,0,2,2,0,0,0,0,0,0,},
            {0,0,2,0,0,0,0,0,0,0,},
            {0,0,2,0,0,0,0,0,0,0,}
    };

    public Tile(Texture2D texture, int tileWidth, int tileHeight)
    {
        _tileWidth = tileWidth;
        _tileHeight = tileHeight;
        Texture = texture;
        totalTiles = Rows * Columns;

    }


    public void Update() {

    }

    public void Draw(SpriteBatch spriteBatch, Vector2 location)
    {

        for (int row = 0; row < tileMap.GetLength(1); row++) {

            for (int col = 0; col < tileMap.GetLength(0); col++) {

                switch (tileMap[row, col]) {
                    case 0:
                        spriteBatch.Draw(Texture, new Rectangle(row * _tileWidth, col * _tileHeight, _tileWidth, _tileHeight), new Rectangle(1 * _tileWidth, 1 * _tileHeight, _tileWidth, _tileHeight), Color.Transparent);
                        break;
                    case 2:
                        spriteBatch.Draw(Texture, new Rectangle(row * _tileWidth, col * _tileHeight, _tileWidth, _tileHeight), new Rectangle(2 * _tileWidth, 2 * _tileHeight, _tileWidth, _tileHeight), Color.Transparent);
                        break;
                    default:
                        break;
                }

            }

主类

public class Main : Microsoft.Xna.Framework.Game {
    // Basic code for drawing.
    GraphicsDeviceManager graphics;
    SpriteBatch spriteBatch;
    Tile test;
    Texture2D texturePack;

    public Main() {
        graphics = new GraphicsDeviceManager(this);
        Content.RootDirectory = "Content";
    }


    protected override void Initialize() {

        base.Initialize();
    }


    protected override void LoadContent() {
        spriteBatch = new SpriteBatch(GraphicsDevice);

        texturePack = Content.Load<Texture2D>("AxiomTileSheet");
        test = new Tile(texturePack, 8, 8);
    }


    protected override void UnloadContent() {
    }


    protected override void Update(GameTime gameTime) {

        if (Keyboard.GetState().IsKeyDown(Keys.Escape))
            this.Exit();


        base.Update(gameTime);
    }


    protected override void Draw(GameTime gameTime) {
        GraphicsDevice.Clear(Color.White);

        spriteBatch.Begin();
        test.Draw(spriteBatch);
        spriteBatch.End();

        base.Draw(gameTime);
    }
}

Answer 1

此

switch (tileMap[row, col])

应该是

switch (tileMap[col, row])

当你使用col为你x值和row为y。

您还需要在矩形计算中切换它。

根据我的经验提供性能的另一个提示（正如Andrew提到的那样，在每种情况下都不值得）而不是每帧都创建新的矩形在你的Tile类中定义2个矩形，并且每帧只更改x和y值

floAr

编辑：颜色问题=============================

您可以使用

完全摆脱switch case构造

public void Draw(SpriteBatch spriteBatch)
        {
    for (int row = 0; row < tileMap.GetLength(1); row++) {
        for (int col = 0; col < tileMap.GetLength(0); col++)
            {
                        spriteBatch.Draw(_texture, new Rectangle(row * _tW, col * _tH, _tW, _tH), new Rectangle(tileMap[row, col] * _tW, tileMap[row, col] * _tH, _tW, _tH), Color.White);
            }
        }
        }

注意：_tH = _tileHeight，_tW = _tileWidth 我测试了它，它对我来说就像一个魅力;）如果要保留开关盒，请确保将Color.White设置为着色颜色（最后一个spritebatch参数）。并且您需要更正开关盒的值，因为在地图定义中使用0和2，但在开关盒中使用0和1。将案例扩展到3（因为看起来你现在有4个瓷砖）也适合我。

所以我认为你的问题是基于错误的颜色和案例结构中的拼写错误。

希望这有帮助:)

瓷砖系统和瓷砖绘图

平铺排序类：

主类

1 个答案: